If 2 is added to each even digit and 1 is subtracted from each odd digit in the number 63145729, then how many digits will appear more than once in the new number thus formed?
Three
Take each digit of 63145729 in turn. Add 2 to even digits and subtract 1 from odd digits.
6 (even) becomes 8. 3 (odd) becomes 2. 1 (odd) becomes 0. 4 (even) becomes 6. 5 (odd) becomes 4. 7 (odd) becomes 6. 2 (even) becomes 4. 9 (odd) becomes 8.
The new number is 82064648.
Now tally each digit: 8 appears twice (first and last), 6 appears twice, 4 appears twice, while 2 and 0 appear once each.
So three digits (8, 6 and 4) appear more than once.
Hence, the number of digits appearing more than once is Three.
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Important Questions from Operations on Place Value
In a certain code language, TOGETHER is coded as 119 and MASTER is coded as 87. How will REVERSE be coded in that language?
In a code language, SOUGHT is written as VRXDEQ. How will ENSURE be written in that language?
In a certain code, if BRDKE is written as AQCJD, then SLEEP will be written in that code as:
In a certain code language, ‘BULB’ is written as ‘190’, ‘CALM’ is written as ‘150’. What is the code for ‘DOES’ in that code language
In a certain code language, RAMP is coded as 3611332. How will DELL be coded in that language?
