If \(\sin^2 A - \cos^2 A = \dfrac{{1}}{{2}}\), find the value of \(\cos^2 A\).
\(1/4\)
Using \(\sin^2 A = 1 - \cos^2 A\):
\((1 - \cos^2 A) - \cos^2 A = \dfrac{{1}}{{2}}\)
\(1 - 2\cos^2 A = \dfrac{{1}}{{2}}\)
\(2\cos^2 A = \dfrac{{1}}{{2}} \implies \cos^2 A = \mathbf{{\dfrac{{1}}{{4}}}}\)
If tanθ =\(\frac{4}{3}\) , then the value of \(\frac{(3sinθ + 2cosθ)}{(3sinθ - 2cosθ)}\) is
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If \(\sin A + \cos A = \dfrac{5}{4}\), find \(\sin 2A\).
If \(\sin A = \dfrac{3}{5}\) and A lies in the second quadrant, find the value of \((\sin A + \cos A)^2\).
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If \(\cot A = x + \dfrac{{1}}{{x}}\), find \(\text{{cosec}}^2 A\).
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If \(\sin \theta =\frac{3}{5}\) and \(\cos \theta =\frac{4}{5}\) , then the value of \(\frac{1+\tan \theta}{1-\cot \theta}\) is: