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Question

If $19^{\text{th}}$ July 2019 was a Friday, what was the day on $21^{\text{st}}$ September 2019?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
Saturday

To determine the day of the week for the date \(21^{\text{st}}\) September 2019, given that \(19^{\text{th}}\) July 2019 was a Friday, we will follow these steps:

  1. Start by calculating the number of days from \(19^{\text{th}}\) July 2019 to \(21^{\text{st}}\) September 2019.
  2. Use this count to determine the day of the week.

Step-by-Step Calculation:

  1. Days in July 2019:
    • There are 31 days in July. Therefore, days remaining after 19th July are:
      • Days remaining in July = 31 - 19 = 12 days.
  2. Days in August 2019:
    • August has 31 days.
  3. Days in September 2019:
    • We consider up to 21st September, which gives us:
      • Days in September = 21 days.

Total number of days from \(19^{\text{th}}\) July to \(21^{\text{st}}\) September:

\(12 + 31 + 21 = 64\) days

Determining the Day of the Week:

  1. Since we know that \(19^{\text{th}}\) July 2019 was a Friday, we add the total days to find the day on \(21^{\text{st}}\) September 2019.
  2. To find the weekday, calculate \(64 \mod 7\). Since \(7\) days constitute a week, we find the remainder of days to advance from Friday.
  3. Starting at Friday, advancing 1 day gives us Saturday.

Thus, \(21^{\text{st}}\) September 2019 was a Saturday.

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