If (11101011) 2is converted to decimal system, then the resulting number is
235
To convert a binary number to a decimal number, we use the concept of place values. In the binary system (base 2), each digit's place value is a power of 2. Starting from the rightmost digit (the least significant bit), the place values are $2^0, 2^1, 2^2$, and so on, increasing by one for each position to the left.
The given binary number is (11101011)₂.
Let's list the digits and their corresponding place values (powers of 2):
| Binary Digit | Position (from right, starting at 0) | Place Value (Power of 2) |
|---|---|---|
| 1 | 7 | $2^7$ |
| 1 | 6 | $2^6$ |
| 1 | 5 | $2^5$ |
| 0 | 4 | $2^4$ |
| 1 | 3 | $2^3$ |
| 0 | 2 | $2^2$ |
| 1 | 1 | $2^1$ |
| 1 | 0 | $2^0$ |
To find the decimal equivalent, we multiply each binary digit by its corresponding place value (power of 2) and then sum up all the results. Remember, any power of 2 multiplied by 0 will be 0.
Let's calculate the powers of 2:
Now, let's perform the multiplication and summation for the binary number (11101011)₂:
$$(11101011)_2 = (1 \times 2^7) + (1 \times 2^6) + (1 \times 2^5) + (0 \times 2^4) + (1 \times 2^3) + (0 \times 2^2) + (1 \times 2^1) + (1 \times 2^0)$$ $$= (1 \times 128) + (1 \times 64) + (1 \times 32) + (0 \times 16) + (1 \times 8) + (0 \times 4) + (1 \times 2) + (1 \times 1)$$ $$= 128 + 64 + 32 + 0 + 8 + 0 + 2 + 1$$ $$= 235$$
So, the binary number (11101011)₂ is equal to 235 in the decimal system.
| Binary Number | Decimal Conversion Process | Decimal Result |
|---|---|---|
| (11101011)₂ | $1 \times 2^7 + 1 \times 2^6 + 1 \times 2^5 + 0 \times 2^4 + 1 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 1 \times 2^0$ | 235 |
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