JOURNEY Letter Pairs: Alphabet Gap Analysis

This solution explains how to find pairs of letters within the word JOURNEY that have the same number of letters separating them as they do in the standard English alphabet. We will analyze the word letter by letter, considering only the forward direction.

Letter Positions in JOURNEY and the Alphabet

First, let's list the letters in the word JOURNEY and their corresponding positions in the English alphabet:

Analyzing Letter Pairs in JOURNEY

We need to check pairs of letters (A, B) such that A appears before B in JOURNEY, and the number of letters between A and B in JOURNEY is the same as the number of letters between A and B in the English alphabet. The number of letters between two positions 'x' and 'y' (where y > x) is calculated as \(y - x - 1\).

Step-by-Step Pair Examination:

• Checking pairs starting with J:

  J and O: In JOURNEY: J (1st), O (2nd) -> 0 letters between. In Alphabet: J (10) to O (15) -> \(15 - 10 - 1 = 4\) letters between (K, L, M, N). Mismatch.

  J and U: In JOURNEY: J (1st), U (3rd) -> \(3 - 1 - 1 = 1\) letter between (O). In Alphabet: J (10) to U (21) -> \(21 - 10 - 1 = 10\) letters between. Mismatch.

  J and R: In JOURNEY: J (1st), R (4th) -> \(4 - 1 - 1 = 2\) letters between (O, U). In Alphabet: J (10) to R (18) -> \(18 - 10 - 1 = 7\) letters between. Mismatch.

  J and N: In JOURNEY: J (1st), N (5th) -> \(5 - 1 - 1 = 3\) letters between (O, U, R). In Alphabet: J (10) to N (14) -> \(14 - 10 - 1 = 3\) letters between (K, L, M). Match! Pair found: (J, N).

  J and E: In JOURNEY, J appears before E. However, alphabetically E comes before J. This is backward direction, so we skip this pair.

  J and Y: In JOURNEY: J (1st), Y (7th) -> \(7 - 1 - 1 = 5\) letters between (O, U, R, N, E). In Alphabet: J (10) to Y (25) -> \(25 - 10 - 1 = 14\) letters between. Mismatch.

• Checking pairs starting with O:

  O and U: In JOURNEY: O (2nd), U (3rd) -> \(3 - 2 - 1 = 0\) letters between. In Alphabet: O (15) to U (21) -> \(21 - 15 - 1 = 5\) letters between. Mismatch.

  O and R: In JOURNEY: O (2nd), R (4th) -> \(4 - 2 - 1 = 1\) letter between (U). In Alphabet: O (15) to R (18) -> \(18 - 15 - 1 = 2\) letters between (P, Q). Mismatch.

  O and N: Backward direction (N comes before O alphabetically). Skip.

  O and E: Backward direction (E comes before O alphabetically). Skip.

  O and Y: In JOURNEY: O (2nd), Y (7th) -> \(7 - 2 - 1 = 4\) letters between (U, R, N, E). In Alphabet: O (15) to Y (25) -> \(25 - 15 - 1 = 9\) letters between. Mismatch.

• Checking pairs starting with U:

  U and R: Backward direction (R comes before U alphabetically). Skip.

  U and N: Backward direction (N comes before U alphabetically). Skip.

  U and E: Backward direction (E comes before U alphabetically). Skip.

  U and Y: In JOURNEY: U (3rd), Y (7th) -> \(7 - 3 - 1 = 3\) letters between (R, N, E). In Alphabet: U (21) to Y (25) -> \(25 - 21 - 1 = 3\) letters between (V, W, X). Match! Pair found: (U, Y).

• Checking pairs starting with R:

  R and N: Backward direction (N comes before R alphabetically). Skip.

  R and E: Backward direction (E comes before R alphabetically). Skip.

  R and Y: In JOURNEY: R (4th), Y (7th) -> \(7 - 4 - 1 = 2\) letters between (N, E). In Alphabet: R (18) to Y (25) -> \(25 - 18 - 1 = 6\) letters between. Mismatch.

• Checking pairs starting with N:

  N and E: Backward direction (E comes before N alphabetically). Skip.

  N and Y: In JOURNEY: N (5th), Y (7th) -> \(7 - 5 - 1 = 1\) letter between (E). In Alphabet: N (14) to Y (25) -> \(25 - 14 - 1 = 10\) letters between. Mismatch.

• Checking pairs starting with E:

  E and Y: In JOURNEY: E (6th), Y (7th) -> \(7 - 6 - 1 = 0\) letters between. In Alphabet: E (5) to Y (25) -> \(25 - 5 - 1 = 19\) letters between. Mismatch.

Conclusion on JOURNEY Letter Pairs

After analyzing all possible pairs in the forward direction, we found two pairs that satisfy the condition:

• (J, N)
• (U, Y)

Therefore, there are 2 such pairs of letters in the word JOURNEY.