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How many of the following can be a vector perpendicular to both the vectors \(2\hat{i} - \hat{j} + \hat{k}\) and \(\hat{i} + \hat{j} + 3\hat{k}\) ? 

I. \(4\hat{i} + 5\hat{j} - 3\hat{k}\) 

II. \(-8\hat{i} - 10\hat{j} + 6\hat{k}\) 

III. \(\frac{1}{50}(-4\hat{i}-5\hat{j}+3\hat{k})\) 

Select the correct answer.

This question was previously asked in
NDA 2 2025 GAT Question Paper (14-Sep-2025)
The correct answer is

All three 

To determine how many of the given vectors can be perpendicular to both vectors \(2\hat{i} - \hat{j} + \hat{k}\) and \(\hat{i} + \hat{j} + 3\hat{k}\), we need to check the orthogonality of each option with both these vectors.

A vector \(\mathbf{v}\) is perpendicular to vectors \(\mathbf{a}\) and \(\mathbf{b}\) if the dot product \(\mathbf{v} \cdot \mathbf{a} = 0\) and \(\mathbf{v} \cdot \mathbf{b} = 0\).

  1. Vector I: \(4\hat{i} + 5\hat{j} - 3\hat{k}\)
    • Calculate the dot product with \(2\hat{i} - \hat{j} + \hat{k}\): \((\mathbf{v}_1 \cdot \mathbf{a}) = 4 \times 2 + 5 \times (-1) + (-3) \times 1 = 8 - 5 - 3 = 0\)
    • Calculate the dot product with \(\hat{i} + \hat{j} + 3\hat{k}\): \((\mathbf{v}_1 \cdot \mathbf{b}) = 4 \times 1 + 5 \times 1 + (-3) \times 3 = 4 + 5 - 9 = 0\)
    • The vector is perpendicular to both vectors.
  2. Vector II: \(-8\hat{i} - 10\hat{j} + 6\hat{k}\)
    • Calculate the dot product with \(2\hat{i} - \hat{j} + \hat{k}\): \((\mathbf{v}_2 \cdot \mathbf{a}) = (-8) \times 2 + (-10) \times (-1) + 6 \times 1 = -16 + 10 + 6 = 0\)
    • Calculate the dot product with \(\hat{i} + \hat{j} + 3\hat{k}\): \((\mathbf{v}_2 \cdot \mathbf{b}) = (-8) \times 1 + (-10) \times 1 + 6 \times 3 = -8 - 10 + 18 = 0\)
    • The vector is perpendicular to both vectors.
  3. Vector III: \(\frac{1}{50}(-4\hat{i} - 5\hat{j} + 3\hat{k})\)
    • Basically considering the vector without scale as \((-4\hat{i} - 5\hat{j} + 3\hat{k})\)
    • Calculate the dot product with \(2\hat{i} - \hat{j} + \hat{k}\): \((\mathbf{v}_3 \cdot \mathbf{a}) = (-4) \times 2 + (-5) \times (-1) + 3 \times 1 = -8 + 5 + 3 = 0\)
    • Calculate the dot product with \(\hat{i} + \hat{j} + 3\hat{k}\): \((\mathbf{v}_3 \cdot \mathbf{b}) = (-4) \times 1 + (-5) \times 1 + 3 \times 3 = -4 - 5 + 9 = 0\)
    • The vector is perpendicular to both vectors.

Since all three vectors satisfy the conditions of being perpendicular to both vectors \(2\hat{i} - \hat{j} + \hat{k}\) and \(\hat{i} + \hat{j} + 3\hat{k}\), the correct answer is All three.

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