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Question

Given below are two statements :
Statement (I) : The dimensions of Planck's constant and angular momentum are same.
Statement (II): In Bohr's model electron revolve around the nucleus only in those orbits for which angular momentum is integral multiple of Planck's constant.
In the light of the above statements, choose the most appropriate answer from the options given below :

The correct answer is
Statement I is correct but Statement II is incorrect

Analyzing Statement I: Dimensions of Planck's Constant and Angular Momentum

Statement I claims that Planck's constant ($h$) and angular momentum ($L$) have the same dimensions.

  • Planck's Constant ($h$): Energy ($E$) is related to frequency ($f$) by the equation $E = hf$. The dimensions are: $[h] = \frac{[E]}{[f]} = \frac{[ML^2T^{-2}]}{[T^{-1}]} = [ML^2T^{-1}]$
  • Angular Momentum ($L$): For a particle of mass ($m$) moving with velocity ($v$) at a distance ($r$), angular momentum is $L = mvr$. The dimensions are: ${[L]} = [m][v][r] = [M][LT^{-1}][L] = [ML^2T^{-1}]$

Since both $[h]$ and $[L]$ are equal to $[ML^2T^{-1}]$, Statement I is correct.

Analyzing Statement II: Bohr's Model Quantization Condition

Statement II states that in Bohr's model, electrons orbit only when their angular momentum is an integral multiple of Planck's constant ($h$).

Bohr's quantum condition for electron orbits is given by:

$L = n\frac{h}{2\pi}$

where $n$ is an integer ($n = 1, 2, 3, \dots$). This means angular momentum must be an integral multiple of $\frac{h}{2\pi}$, not $h$. Therefore, Statement II is incorrect.

Conclusion

Based on the analysis:

  • Statement I is correct.
  • Statement II is incorrect.

Thus, the most appropriate answer is that Statement I is correct but Statement II is incorrect.

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Important Questions from Modern Physics

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    (Given: The magnitude of charge of an electron is $e$ and mass is $m$, $h$ is Planck's constant and $c$ is velocity of light. Take the magnetic field exists throughout the path of electron)

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