Choose the correct logic circuit for the given truth table having inputs A and B.
Truth Table Analysis
We are given a truth table with two inputs, A and B, and one output, Y:
| A | B | Y |
|---|---|---|
| 0 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 0 | 1 |
| 1 | 1 | 1 |
Deriving the Logic Function
By examining the truth table, we can determine the relationship between the inputs (A, B) and the output (Y):
- When A is 0, Y is 0 irrespective of the value of B.
- When A is 1, Y is 1 irrespective of the value of B.
This shows that the output Y is always equal to the input A. Therefore, the logic function is:
$ Y = A $
Selecting the Correct Logic Circuit
The task is to find the logic circuit diagram that implements the function $ Y = A $. This means the circuit should output the value of input A directly, and input B should not affect the output.
Comparing the given truth table with standard logic gates:
- AND gate (Y = A AND B): Output is 1 only when both A and B are 1. (Doesn't match rows 2 and 3).
- OR gate (Y = A OR B): Output is 1 if either A or B (or both) is 1. (Doesn't match row 2 where A=0, B=1, but Y=0).
The function $ Y = A $ is directly implemented by a circuit where A is passed through to Y, and B is effectively ignored. Option D provides the circuit diagram corresponding to this logic.
Similar Questions
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Important Questions from Modern Physics
- A voltage regulating circuit consisting of Zener diode, having break-down voltage of 10 V and maximum power dissipation of 0.4 W, is operated at 15 V. The approximate value of protective resistance in this circuit is ______ $\Omega$.
- A particle having electric charge $3 \times 10^{-19}\text{ C}$ and mass $6 \times 10^{-27}\text{ kg}$ is accelerated by applying an electric potential of $1.21\text{ V}$. Wavelength of the matter wave associated with the particle is $\alpha \times 10^{-12}\text{ m}$. The value of $\alpha$ is __________. (Take Planck's constant $= 6.6 \times 10^{-34}\text{ J.s}$)
- The average energy released per fission for the nucleus of ${}^{235}_{92}\text{U}$ is $190 \text{ MeV}$. When all the atoms of $47 \text{ g}$ pure ${}^{235}_{92}\text{U}$ undergo fission process, the energy released is $\alpha \times 10^{23} \text{ MeV}$. The value of $\alpha$ is ________.
(Avogadro Number = $6 \times 10^{23} \text{ per mole}$) - The energy released when $\frac{7}{17.13} \text{ kg}$ of ${}^7_3\text{Li}$ is converted into ${}^4_2\text{He}$ by proton bombardment is $\alpha \times 10^{32} \text{ eV}$. The value of $\alpha$ is _________. (Nearest integer)
(Mass of ${}^7_3\text{Li} = 7.0183 \text{ u}$, mass of ${}^4_2\text{He} = 4.004 \text{ u}$, mass of proton = $1.008 \text{ u}$ and $1 \text{ u} = 931 \text{ MeV/}c^2$ and Avogadro number $= 6.0 \times 10^{23}$) - A nuclear physicist performed an experiment on the scattering of alpha particles by thin metal foil of gold. The alpha particles were accelerated up to kinetic energy $3.2$ Mev. The estimation of the radius of the nucleus of gold element $(Z = 79)$ by him is $\times 10^{-16}$ m
(Take $\frac{1}{4\pi \epsilon_0} = 9\times10^9 \frac{Nm^2}{C^2}$)
