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Question

Choose the correct logic circuit for the given truth table having inputs A and B. 

\[\begin{array}{|c|c|c|} \hline A & B & Y \\ \hline 0 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \hline \end{array}\]

The correct answer is

Truth Table Analysis

We are given a truth table with two inputs, A and B, and one output, Y:

A B Y
0 0 0
0 1 0
1 0 1
1 1 1

Deriving the Logic Function

By examining the truth table, we can determine the relationship between the inputs (A, B) and the output (Y):

  • When A is 0, Y is 0 irrespective of the value of B.
  • When A is 1, Y is 1 irrespective of the value of B.

This shows that the output Y is always equal to the input A. Therefore, the logic function is:

$ Y = A $

Selecting the Correct Logic Circuit

The task is to find the logic circuit diagram that implements the function $ Y = A $. This means the circuit should output the value of input A directly, and input B should not affect the output.

Comparing the given truth table with standard logic gates:

  • AND gate (Y = A AND B): Output is 1 only when both A and B are 1. (Doesn't match rows 2 and 3).
  • OR gate (Y = A OR B): Output is 1 if either A or B (or both) is 1. (Doesn't match row 2 where A=0, B=1, but Y=0).

The function $ Y = A $ is directly implemented by a circuit where A is passed through to Y, and B is effectively ignored. Option D provides the circuit diagram corresponding to this logic.

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