This solution calculates the ratio of the largest wavelengths for the Lyman and Balmer series in the hydrogen atom using the Rydberg formula.
The wavelength ($\lambda$) of a spectral line emitted by a hydrogen atom is given by the Rydberg formula:
$ \frac{1}{\lambda} = R \left( \frac{1}{n_f^2} - \frac{1}{n_i^2} \right) $Where '$R$' is the Rydberg constant, '$n_f$' is the principal quantum number of the final energy level, and '$n_i$' is the principal quantum number of the initial energy level. The largest wavelength ($\lambda_{max}$) corresponds to the smallest energy difference, which occurs for the transition from the lowest possible initial state to the final state.
The Lyman series involves transitions to the final state $n_f = 1$. The largest wavelength occurs when the electron transitions from the next lowest state, $n_i = 2$.
Using the formula:
$ \frac{1}{\lambda_{L,max}} = R \left( \frac{1}{1^2} - \frac{1}{2^2} \right) = R \left( 1 - \frac{1}{4} \right) = R \left( \frac{3}{4} \right) $Therefore, the largest wavelength for the Lyman series is:
$ \lambda_{L,max} = \frac{4}{3R} $The Balmer series involves transitions to the final state $n_f = 2$. The largest wavelength occurs when the electron transitions from the next lowest state, $n_i = 3$.
Using the formula:
$ \frac{1}{\lambda_{B,max}} = R \left( \frac{1}{2^2} - \frac{1}{3^2} \right) = R \left( \frac{1}{4} - \frac{1}{9} \right) = R \left( \frac{9 - 4}{36} \right) = R \left( \frac{5}{36} \right) $Therefore, the largest wavelength for the Balmer series is:
$ \lambda_{B,max} = \frac{36}{5R} $The question asks for the ratio of the largest wavelength of the Lyman series to that of the Balmer series:
$ \frac{\lambda_{L,max}}{\lambda_{B,max}} = \frac{\left( \frac{4}{3R} \right)}{\left( \frac{36}{5R} \right)} $Simplify the ratio:
$ \frac{\lambda_{L,max}}{\lambda_{B,max}} = \frac{4}{3R} \times \frac{5R}{36} = \frac{4 \times 5}{3 \times 36} = \frac{20}{108} $Reducing the fraction gives:
$ \frac{20}{108} = \frac{5}{27} $The ratio is $5:27$.
Match the LIST-I with LIST-II
| LIST-I | LIST-II | ||
| A. | $^1_0n + ^{235}_{92}U \rightarrow ^{140}_{54}Xe + ^{94}_{38}Sr + 2^1_0n$ | I. | Chemical reaction |
| B. | $2H_2+O_2\rightarrow 2H_2O$ | II. | Fusion with +ve Q value |
| C. | $^1_1H+^2_1H \rightarrow ^3_2He + ^1_0n$ | III. | Fission |
| D. | $^1_1H+^1_1H \rightarrow ^2_1H+^0_1e$ | IV. | Fusion with -ve Q value |
Choose the correct answer from the options given below:
Choose the correct logic circuit for the given truth table having inputs A and B.
\[\begin{array}{|c|c|c|} \hline A & B & Y \\ \hline 0 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \hline \end{array}\]Two coherent monochromatic light beams of intensities 4I and 9I are superimposed. The difference between the maximum and minimum intensities in the resulting interference pattern is xI. The value of x is __________
Considering Bohr's atomic model for hydrogen atom :
(A) the energy of H atom in ground state is same as energy of $He^+$ ion in its first excited state.
(B) the energy of H atom in ground state is same as that for $Li^{++}$ ion in its second excited state.
(C) the energy of H atom in ground state is same as that of $He^+$ ion for its ground state.
(D) the energy of $He^+$ ion in its first excited state is same as that for $Li^{++}$ ion in its ground state.
Choose the correct answer from the options given below :
A monochromatic light is incident on a metallic plate having work function $\phi$. An electron, emitted normally to the plate from a point A with maximum kinetic energy, enters a constant magnetic field, perpendicular to the initial velocity of electron. The electron passes through a curve and hits back the plate at a point B. The distance between A and B is:
(Given: The magnitude of charge of an electron is $e$ and mass is $m$, $h$ is Planck's constant and $c$ is velocity of light. Take the magnetic field exists throughout the path of electron)
Match the LIST-I with LIST-II
| LIST-I | LIST-II | ||
| A. | $^1_0n + ^{235}_{92}U \rightarrow ^{140}_{54}Xe + ^{94}_{38}Sr + 2^1_0n$ | I. | Chemical reaction |
| B. | $2H_2+O_2\rightarrow 2H_2O$ | II. | Fusion with +ve Q value |
| C. | $^1_1H+^2_1H \rightarrow ^3_2He + ^1_0n$ | III. | Fission |
| D. | $^1_1H+^1_1H \rightarrow ^2_1H+^0_1e$ | IV. | Fusion with -ve Q value |
Choose the correct answer from the options given below:
Choose the correct logic circuit for the given truth table having inputs A and B.
\[\begin{array}{|c|c|c|} \hline A & B & Y \\ \hline 0 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \hline \end{array}\]Two coherent monochromatic light beams of intensities 4I and 9I are superimposed. The difference between the maximum and minimum intensities in the resulting interference pattern is xI. The value of x is __________
Considering Bohr's atomic model for hydrogen atom :
(A) the energy of H atom in ground state is same as energy of $He^+$ ion in its first excited state.
(B) the energy of H atom in ground state is same as that for $Li^{++}$ ion in its second excited state.
(C) the energy of H atom in ground state is same as that of $He^+$ ion for its ground state.
(D) the energy of $He^+$ ion in its first excited state is same as that for $Li^{++}$ ion in its ground state.
Choose the correct answer from the options given below :
A monochromatic light is incident on a metallic plate having work function $\phi$. An electron, emitted normally to the plate from a point A with maximum kinetic energy, enters a constant magnetic field, perpendicular to the initial velocity of electron. The electron passes through a curve and hits back the plate at a point B. The distance between A and B is:
(Given: The magnitude of charge of an electron is $e$ and mass is $m$, $h$ is Planck's constant and $c$ is velocity of light. Take the magnetic field exists throughout the path of electron)