Geometrically Re (z 2– i) = 2, where \(i = \sqrt { - 1} \) and Re is the real part, represents
Rectangular hyperbola
The question asks for the geometric shape represented by the equation \( \text{Re} (z^2 - i) = 2 \), where \( z \) is a complex number and \( \text{Re} \) denotes the real part of the complex number.
Let the complex number \( z \) be represented as \( z = x + iy \), where \( x \) and \( y \) are real numbers representing the real and imaginary parts, respectively. The geometric representation will be in the Cartesian plane using coordinates \( (x, y) \).
First, calculate \( z^2 \):
\( z^2 = (x + iy)^2 \)
Expanding this, we get:
\( z^2 = x^2 + 2(x)(iy) + (iy)^2 \)
\( z^2 = x^2 + 2ixy + i^2 y^2 \)
Since \( i^2 = -1 \), this becomes:
\( z^2 = x^2 + 2ixy - y^2 \)
\( z^2 = (x^2 - y^2) + i(2xy) \)
Now, subtract \( i \) from \( z^2 \):
\( z^2 - i = (x^2 - y^2) + i(2xy) - i \)
\( z^2 - i = (x^2 - y^2) + i(2xy - 1) \)
The expression \( z^2 - i \) is in the form \( A + iB \), where \( A = x^2 - y^2 \) is the real part and \( B = 2xy - 1 \) is the imaginary part.
The equation given is \( \text{Re} (z^2 - i) = 2 \).
Therefore, we take the real part of \( z^2 - i \) and set it equal to 2:
\( \text{Re} (z^2 - i) = x^2 - y^2 \)
So, the equation in terms of \( x \) and \( y \) is:
\( x^2 - y^2 = 2 \)
The equation \( x^2 - y^2 = 2 \) is in the standard form of a hyperbola centered at the origin:
\( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \) or \( \frac{y^2}{b^2} - \frac{x^2}{a^2} = 1 \)
Our equation \( x^2 - y^2 = 2 \) can be rewritten as:
\( \frac{x^2}{2} - \frac{y^2}{2} = 1 \)
Comparing this to the standard form \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \), we see that \( a^2 = 2 \) and \( b^2 = 2 \). This means \( a = \sqrt{2} \) and \( b = \sqrt{2} \).
The equation \( \frac{x^2}{2} - \frac{y^2}{2} = 1 \) represents a hyperbola with \( a = b \).
A hyperbola where the lengths of the semi-major and semi-minor axes are equal (\( a = b \)) is called a rectangular hyperbola (or equilateral hyperbola). For such a hyperbola, the asymptotes are perpendicular to each other.
The equation \( \text{Re} (z^2 - i) = 2 \) transforms into \( x^2 - y^2 = 2 \) in the Cartesian plane, which is the equation of a rectangular hyperbola.
| Complex Equation | Cartesian Equation | Geometric Shape |
|---|---|---|
| \( \text{Re} (z^2 - i) = 2 \) | \( x^2 - y^2 = 2 \) | Rectangular Hyperbola |
| Shape | Standard Equation (Centered at Origin) | Key Property |
|---|---|---|
| Circle | \( x^2 + y^2 = r^2 \) | Constant distance from center (radius). |
| Ellipse | \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \) | Sum of distances from two foci is constant. |
| Parabola | \( y^2 = 4ax \) or \( x^2 = 4ay \) | Constant distance from a focus and a directrix line. |
| Hyperbola | \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \) or \( \frac{y^2}{b^2} - \frac{x^2}{a^2} = 1 \) | Difference of distances from two foci is constant. |
| Rectangular Hyperbola | \( x^2 - y^2 = a^2 \) or \( y^2 - x^2 = a^2 \) (Specific Case) | A hyperbola where asymptotes are perpendicular (\( a=b \)). |
Complex numbers provide a powerful way to represent points in a 2D plane (the complex plane or Argand plane). An equation involving a complex variable \( z \) often translates into a geometric shape in this plane.
In this specific problem, evaluating \( z^2 - i \) and then taking the real part allowed us to translate the complex equation \( \text{Re} (z^2 - i) = 2 \) into the familiar Cartesian equation \( x^2 - y^2 = 2 \), which is a rectangular hyperbola.
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