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Question

Geometrically Re (z 2– i) = 2, where \(i = \sqrt { - 1} \) and Re is the real part, represents

This question was previously asked in
NDA I 2017 GAT Previous Year Paper (23-Apr-2017)
The correct answer is

Rectangular hyperbola

Understanding the Geometric Representation of Complex Equations

The question asks for the geometric shape represented by the equation \( \text{Re} (z^2 - i) = 2 \), where \( z \) is a complex number and \( \text{Re} \) denotes the real part of the complex number.

Let the complex number \( z \) be represented as \( z = x + iy \), where \( x \) and \( y \) are real numbers representing the real and imaginary parts, respectively. The geometric representation will be in the Cartesian plane using coordinates \( (x, y) \).

Step-by-Step Analysis of the Equation

  1. Substitute \( z = x + iy \) into the expression \( z^2 - i \):

    First, calculate \( z^2 \):

    \( z^2 = (x + iy)^2 \)

    Expanding this, we get:

    \( z^2 = x^2 + 2(x)(iy) + (iy)^2 \)

    \( z^2 = x^2 + 2ixy + i^2 y^2 \)

    Since \( i^2 = -1 \), this becomes:

    \( z^2 = x^2 + 2ixy - y^2 \)

    \( z^2 = (x^2 - y^2) + i(2xy) \)

    Now, subtract \( i \) from \( z^2 \):

    \( z^2 - i = (x^2 - y^2) + i(2xy) - i \)

    \( z^2 - i = (x^2 - y^2) + i(2xy - 1) \)

  2. Find the Real Part:

    The expression \( z^2 - i \) is in the form \( A + iB \), where \( A = x^2 - y^2 \) is the real part and \( B = 2xy - 1 \) is the imaginary part.

    The equation given is \( \text{Re} (z^2 - i) = 2 \).

    Therefore, we take the real part of \( z^2 - i \) and set it equal to 2:

    \( \text{Re} (z^2 - i) = x^2 - y^2 \)

    So, the equation in terms of \( x \) and \( y \) is:

    \( x^2 - y^2 = 2 \)

  3. Identify the Geometric Shape:

    The equation \( x^2 - y^2 = 2 \) is in the standard form of a hyperbola centered at the origin:

    \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \) or \( \frac{y^2}{b^2} - \frac{x^2}{a^2} = 1 \)

    Our equation \( x^2 - y^2 = 2 \) can be rewritten as:

    \( \frac{x^2}{2} - \frac{y^2}{2} = 1 \)

    Comparing this to the standard form \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \), we see that \( a^2 = 2 \) and \( b^2 = 2 \). This means \( a = \sqrt{2} \) and \( b = \sqrt{2} \).

  4. Characteristics of the Shape:

    The equation \( \frac{x^2}{2} - \frac{y^2}{2} = 1 \) represents a hyperbola with \( a = b \).

    A hyperbola where the lengths of the semi-major and semi-minor axes are equal (\( a = b \)) is called a rectangular hyperbola (or equilateral hyperbola). For such a hyperbola, the asymptotes are perpendicular to each other.

Conclusion on Geometric Representation

The equation \( \text{Re} (z^2 - i) = 2 \) transforms into \( x^2 - y^2 = 2 \) in the Cartesian plane, which is the equation of a rectangular hyperbola.

Complex Equation Cartesian Equation Geometric Shape
\( \text{Re} (z^2 - i) = 2 \) \( x^2 - y^2 = 2 \) Rectangular Hyperbola

Revision Table: Conic Sections Overview

Shape Standard Equation (Centered at Origin) Key Property
Circle \( x^2 + y^2 = r^2 \) Constant distance from center (radius).
Ellipse \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \) Sum of distances from two foci is constant.
Parabola \( y^2 = 4ax \) or \( x^2 = 4ay \) Constant distance from a focus and a directrix line.
Hyperbola \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \) or \( \frac{y^2}{b^2} - \frac{x^2}{a^2} = 1 \) Difference of distances from two foci is constant.
Rectangular Hyperbola \( x^2 - y^2 = a^2 \) or \( y^2 - x^2 = a^2 \) (Specific Case) A hyperbola where asymptotes are perpendicular (\( a=b \)).

Additional Information: Complex Numbers and Geometry

Complex numbers provide a powerful way to represent points in a 2D plane (the complex plane or Argand plane). An equation involving a complex variable \( z \) often translates into a geometric shape in this plane.

  • The form \( z = x + iy \) is the connection between complex numbers and Cartesian coordinates \( (x, y) \).
  • Operations on \( z \), like squaring \( z^2 \) or taking the real part \( \text{Re}(z) \), correspond to transformations or conditions that define loci (geometric shapes) in the \( x-y \) plane.
  • Understanding how to convert a complex equation into an equation involving \( x \) and \( y \) is crucial for identifying the geometric shape it represents. This involves substituting \( z = x + iy \) and separating the real and imaginary parts.

In this specific problem, evaluating \( z^2 - i \) and then taking the real part allowed us to translate the complex equation \( \text{Re} (z^2 - i) = 2 \) into the familiar Cartesian equation \( x^2 - y^2 = 2 \), which is a rectangular hyperbola.

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