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Question

Four letter-clusters have been given, out of which three are alike in some manner and one is different. Select the letter-cluster that is different

This question was previously asked in
SSC CGL 2020 Tier-II (English) Previous Year Paper (29-Jan-2022)
The correct answer is

ZTOl

Analyzing Letter Clusters to Find the Odd One Out

In this question, we are given four letter clusters: OIDZ, ZTOl, AUPL, and JDYU. We need to find the one that is different from the other three based on some common pattern.

Let's examine each letter cluster and look for possible patterns. Common patterns involve letter positions in the alphabet, vowel and consonant counts, difference between letter positions, etc.

Let's consider the count of vowels (A, E, I, O, U) in each cluster. For this type of puzzle, the letter 'Y' is sometimes treated as a vowel, depending on the pattern required. Let's count vowels in each cluster:

  • OIDZ: Contains the letters O, I, D, Z. Vowels are O and I. Number of vowels = 2.
  • ZTOl: Contains the letters Z, T, O, l. Assuming 'l' is the lowercase letter L (a consonant). The vowel is O. Number of vowels = 1.
  • AUPL: Contains the letters A, U, P, L. Vowels are A and U. Number of vowels = 2.
  • JDYU: Contains the letters J, D, Y, U. Assuming 'Y' is treated as a vowel for this pattern. Vowels are Y and U. Number of vowels = 2.

Let's summarize the vowel counts in a table:

Letter Cluster Letters Vowels Number of Vowels
OIDZ O, I, D, Z O, I 2
ZTOl Z, T, O, l (lowercase L) O 1
AUPL A, U, P, L A, U 2
JDYU J, D, Y, U Y, U (assuming Y is a vowel) 2

Based on the vowel count, we observe the following:

  • OIDZ has 2 vowels.
  • ZTOl has 1 vowel.
  • AUPL has 2 vowels.
  • JDYU has 2 vowels (assuming Y is treated as a vowel).

Three of the letter clusters (OIDZ, AUPL, JDYU) have 2 vowels each, while one letter cluster (ZTOl) has only 1 vowel. This difference in the number of vowels forms the pattern that makes ZTOl the odd one out.

Conclusion

By analyzing the number of vowels in each letter cluster, we found that OIDZ, AUPL, and JDYU each contain 2 vowels (treating Y as a vowel in JDYU), whereas ZTOl contains only 1 vowel. Therefore, ZTOl is different from the other three clusters.

Revision Table: Letter Cluster Analysis

Letter Cluster Vowel Count Pattern Fit
OIDZ 2 Fits the '2 Vowels' pattern
ZTOl 1 Does not fit the '2 Vowels' pattern
AUPL 2 Fits the '2 Vowels' pattern
JDYU 2 Fits the '2 Vowels' pattern (assuming Y is vowel)

Additional Information: Letter Puzzles and Reasoning

Letter cluster puzzles are common in logical reasoning sections of exams. They test your ability to identify patterns based on various properties of letters, such as:

  • Alphabetical Position: The position of letters (A=1, B=2, ... Z=26). Patterns can involve differences, sums, or other mathematical operations on these positions.
  • Vowels and Consonants: The type of letters (vowel or consonant) and their counts within the cluster.
  • Sequence: Patterns based on skipping letters in the alphabet or moving forward/backward a certain number of steps.
  • Symmetry or Structure: Less common, but sometimes relates to visual properties or symmetry.

When solving such problems, it's helpful to systematically check for these common patterns. Sometimes, the letter 'Y' can act as either a vowel or a consonant, depending on which assumption creates a consistent pattern among three of the options.

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