Question
For the set of numbers 2, 3, 7, 8, and 10, the second-order moment about the origin 4 is:
This question was previously asked in
SSC CGL 2024 (Tier-I) Previous Year Paper (17-Sep-2024) (Shift 3)
The correct answer is
13.2
Second-order moment about 4 is \(\frac{1}{n}\sum (x_i - 4)^2 = \frac{(2-4)^2 + (3-4)^2 + \dots + (10-4)^2}{5} = \frac{66}{5} = 13.2\).
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