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Question

For the network given below:-

The state equation is:-

The correct answer is

$\frac{d}{dt} \begin{bmatrix} V_c \\ i_L \end{bmatrix} = \begin{bmatrix} 0 & -\frac{1}{C} \\ \frac{1}{L} & -\frac{R}{L} \end{bmatrix} \begin{bmatrix} V_c \\ i_L \end{bmatrix} + \begin{bmatrix} \frac{1}{C} \\ 0 \end{bmatrix} i$

The given network is a simple RLC circuit. To derive the state-space equations, we need to express the circuit's dynamics in terms of its state variables. For this circuit, the state variables are:

  • \(V_c\): the voltage across the capacitor.
  • \(i_L\): the current through the inductor.

The state-space representation for an RLC circuit can be given by:

  • \(\frac{dV_c}{dt} = \frac{1}{C}(i - i_L)\), which arises from the relationship \(i_c = C \frac{dV_c}{dt}\).
  • \(\frac{di_L}{dt} = \frac{1}{L}(V_c - Ri_L)\), from the inductor's voltage-current relation.

Thus, using matrix notation, the state equations become:

\(\frac{d}{dt} \begin{bmatrix} V_c \\ i_L \end{bmatrix} = \begin{bmatrix} 0 & -\frac{1}{C} \\ \frac{1}{L} & -\frac{R}{L} \end{bmatrix} \begin{bmatrix} V_c \\ i_L \end{bmatrix} + \begin{bmatrix} \frac{1}{C} \\ 0 \end{bmatrix} i\)

This equation matches the given correct answer option:

\(\frac{d}{dt} \begin{bmatrix} V_c \\ i_L \end{bmatrix} = \begin{bmatrix} 0 & -\frac{1}{C} \\ \frac{1}{L} & -\frac{R}{L} \end{bmatrix} \begin{bmatrix} V_c \\ i_L \end{bmatrix} + \begin{bmatrix} \frac{1}{C} \\ 0 \end{bmatrix} i\)

This formulation reflects Kirchoff's laws for voltage and current in an RLC circuit, properly distinguishing between the effects of capacitance and inductance.

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Important Questions from State Space Representation

  1. A discrete system is represented by the difference equation

    \(\left[ {\begin{array}{*{20}{c}} {{X_1}\left( {k + 1} \right)}\\ {{X_2}\left( {k + 1} \right)} \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} a&{a - 1}\\ {a + 1}&a \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {{X_1}\left( k \right)}\\ {{X_2}\left( k \right)} \end{array}} \right]\)

    It has initial conditions X1(0) = 1; X2(0) = 0. The pole locations of the system for a = 1, are
  2. Arrange the following in the sequence of steps for writing STATE EQUATION:-
    A. Choose a normal tree for a network
    B. Take either voltages or charges across the capacitor, which are tree branches and eithercurrents or fluxes through inductors, which are co-tree chords
    C. Write independent KVL, KCL and branch voltage current relations (VCR).
    D. Rearrange the vector matrix differential equation for state variable representation.
    E. Eliminate all non-state variables of the network
    Choose the correct answer from the options given below:

  3. Consider the state-space representation of a system
    $ \dot{x} = Ax + Bu $
    where $x$ is the state vector, $u$ is the input, $A$ is the system matrix and $B$ is the input matrix. Choose the matrix $A$ from the following options such that the system has a pole at the origin.
  4. The state and output equations for a control system are:
    $$\dot{x} = \begin{bmatrix} -4 & -1.5 \\ 4 & 0 \end{bmatrix}x + \begin{bmatrix} 2 \\ 0 \end{bmatrix}u$$
    $$y = \begin{bmatrix} 1.5 & 0.625 \end{bmatrix}x$$
    Which of the following expressions correctly represents the transfer function $\frac{Y(s)}{U(s)}$ of the system with zero initial conditions?
  5. The state-space model of a system is given as
    $$ \begin{bmatrix} \dot{x}_1 \\ \dot{x}_2 \end{bmatrix} = \begin{bmatrix} 1 & 0 \\ 1 & 1 \end{bmatrix} \begin{bmatrix} x_1 \\ x_2 \end{bmatrix} + \begin{bmatrix} 1 \\ 1 \end{bmatrix} u(t) $$
    where u(t) is a unit step input occurring at t = 0 and $x(0) = \begin{bmatrix} 1 \\ 0 \end{bmatrix}$.
    The time response of the system is
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