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Question

For a simple enzyme that follows Michaelis-Menten kinetics, kinetic data was collected in the absence (dotted line, -I), or presence (solid line, +I) of an uncompetitive inhibitor (I). Which one of the following Eadie-Hofstee plots best describes the expected result?

($v_0$ = initial velocity, $[S]$ = free substrate concentration)

The correct answer is

This question asks to identify the correct Eadie-Hofstee plot for an enzyme exhibiting Michaelis-Menten kinetics in the presence of an uncompetitive inhibitor.

Understanding Eadie-Hofstee Plots

The Eadie-Hofstee plot graphs the initial velocity ($v_0$) on the y-axis against the ratio $v_0/[S]$ (where $[S]$ is substrate concentration) on the x-axis. The equation is represented as: $v_0 = V_{max} - K_m \frac{v_0}{[S]}$ This equation is in the form $y = c + mx$, where:

  • $y = v_0$
  • $x = v_0/[S]$
  • $c = V_{max}$ (y-intercept)
  • $m = -K_m$ (slope)

Effect of Uncompetitive Inhibition

An uncompetitive inhibitor binds exclusively to the enzyme-substrate (ES) complex. This type of inhibition affects the enzyme kinetics by:

  • Decreasing the maximum velocity ($V_{max}$).
  • Decreasing the Michaelis constant ($K_m$).

Eadie-Hofstee Plot Changes with Uncompetitive Inhibition

Based on the Eadie-Hofstee equation and the effects of uncompetitive inhibition:

  • Y-intercept ($V_{max}$): Since $V_{max}$ decreases, the y-intercept of the plot shifts downwards in the presence of the inhibitor.
  • Slope ($-K_m$): Since $K_m$ decreases, the value of $-K_m$ becomes less negative (i.e., the slope increases towards zero). The slope becomes less steep.

Therefore, the line representing the inhibited enzyme (+I, solid line) should be positioned below the uninhibited enzyme line (-I, dotted line) and have a less steep slope.

Analyzing the Options

We need to find the plot that shows a decreased y-intercept and a less steep slope.

  • Option 1 (Plot 1): Shows a decreased y-intercept and a less steep slope. The lines intersect on the x-axis. This is consistent with the theoretical model of uncompetitive inhibition.
  • Option 2 (Plot 2): Shows a decreased y-intercept but a steeper slope (more negative). This pattern is characteristic of competitive inhibition.
  • Option 3 (Plot 3): Shows a decreased y-intercept, but the slope change is less clear or potentially constant. This does not perfectly fit the expected changes for uncompetitive inhibition.
  • Option 4 (Plot D): Shows a decreased y-intercept ($V_{max}$) and a less steep slope (increased $-K_m$, meaning decreased $K_m$). The solid line (+I) is below and less steep than the dotted line (-I). This plot visually matches the expected changes in intercept and slope for uncompetitive inhibition.

Plot 4 (Option D) best depicts the decrease in both $V_{max}$ (y-intercept) and $K_m$ (slope) characteristic of uncompetitive inhibition on an Eadie-Hofstee plot.

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Important Questions from Enzyme Kinetics Competitive Inhibition

  1. The CORRECT statement(s) about a competitive inhibitor of an enzyme is/are
  2. Researchers measure the activity of an enzyme in the presence of an inhibitor. They observe that
    • $V_{\text{max}}$ of the enzyme remains unchanged at saturating substrate concentration
    • $K_m$ increases compared to uninhibited enzyme
    Which type of inhibition is most consistent with these observations?
  3. The kinetics of an enzyme in the presence (+I) or absence (-I) of a reversible inhibitor is described in the following graph.

     If concentration of the reversible inhibitor in +I experiment was equal to $3.0 \times 10^{-3}$ M, then the dissociation constant for the enzyme-inhibitor complex is

  4. In an in vitro dehydrogenation reaction of succinate catalyzed by succinate dehydrogenase, malonate is added. Which one of the following curves represents the effect of malonate on the catalysis of succinate dehydrogenase?
  5. Aromatase inhibitors are often prescribed for post-menopausal women to treat estrogen receptor positive breast cancer patients, because these class of drugs
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