The question asks for the measure of an interior angle of a regular polygon with 10 sides.
For any regular polygon with $n$ sides, the formula to calculate the measure of each interior angle is:
$ \text{Interior Angle} = \frac{(n-2) \times 180^\circ}{n} $
In this case, the polygon has 10 sides, so $n = 10$. Plugging this value into the formula:
$ \text{Interior Angle} = \frac{(10-2) \times 180^\circ}{10} $
$ \text{Interior Angle} = \frac{8 \times 180^\circ}{10} $
$ \text{Interior Angle} = \frac{1440^\circ}{10} $
$ \text{Interior Angle} = 144^\circ $
Therefore, the interior angle between the sides of a regular polygon with 10 sides is 144 degrees.
In the given figure, $P, Q$, and $R$ are three points on a circle of radius 10 cm with $O$ as its center, $\overline{PQ} = \overline{RQ}$, and $\angle PQR = 45^\circ$. The figure is representative.
The area of the shaded region $PQRO$ is ______________ cm$^2$.
