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Question

For a distribution with mean, median, mode and standard deviation 25, 24, 26 and 5 respectively, Karl Pearson's coefficient of skewness equals to:

This question was previously asked in
SSC CGL 2018 (Tier 2) Statistics Previous Year Paper (22-feb-2018)
The correct answer is

-0.20

Karl Pearson's coefficient of skewness (using mode) is:

\[SK_P=\frac{\text{Mean}-\text{Mode}}{\sigma}\]

Substituting Mean = 25, Mode = 26, \(\sigma=5\):

\[SK_P=\frac{25-26}{5}=\frac{-1}{5}=-0.20\]

The negative value is consistent with Mode > Mean, indicating a slightly left-skewed distribution. Hence the coefficient is -0.20.

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