Parasite Fish Calculation
The problem asks for the number of fish that have one or more parasites. We are given the total number of fish and the number of fish that have no parasites.
- Total number of fish = 50
- Number of fish with no ectoparasite = 12
The fish population can be divided into two groups: those with no parasites and those with at least one parasite.
To find the number of fish with at least one parasite, we subtract the number of fish with no parasites from the total number of fish.
Mathematical Calculation:
Number of fish with at least one parasite = Total fish - Number of fish with no ectoparasite
$ \text{Number of fish with at least one parasite} = 50 - 12 $
$ \text{Number of fish with at least one parasite} = 38 $
Therefore, 38 fish had at least one parasite.
Important Questions from Basics of Probability
Suppose a 5-bit message is transmitted from a source to a destination through a noisy channel. The probability that a bit of the message gets flipped during transmission is 0.01. Flipping of each bit is independent of one another. The probability that the message is delivered error-free to the destination is ______ . (rounded off to three decimal places)
- A quadratic polynomial $(x - \alpha)(x - \beta)$ over complex numbers is said to be square invariant if $(x - \alpha)(x - \beta) = (x - \alpha^2)(x - \beta^2)$. Suppose from the set of all square invariant quadratic polynomials we choose one at random.
The probability that the roots of the chosen polynomial are equal is ____________ (rounded off to one decimal place) For a distribution with mean, median, mode and standard deviation 25, 24, 26 and 5 respectively, Karl Pearson's coefficient of skewness equals to:
Suppose two distributions have the same mean, same standard deviation and are equally skewed, but the first distribution is more peaked than the
other. This feature of the frequency distributions in which they are different are called:For two equally likely, exhaustive and independent events A and B, P(A ∩ B) is:
