Parasite Fish Calculation
The problem asks for the number of fish that have one or more parasites. We are given the total number of fish and the number of fish that have no parasites.
- Total number of fish = 50
- Number of fish with no ectoparasite = 12
The fish population can be divided into two groups: those with no parasites and those with at least one parasite.
To find the number of fish with at least one parasite, we subtract the number of fish with no parasites from the total number of fish.
Mathematical Calculation:
Number of fish with at least one parasite = Total fish - Number of fish with no ectoparasite
$ \text{Number of fish with at least one parasite} = 50 - 12 $
$ \text{Number of fish with at least one parasite} = 38 $
Therefore, 38 fish had at least one parasite.
Important Questions from Basics of Probability
If the data are skewed, which option of central tendency measure is the most unreliable indicator?
In a negatively skewed distribution
If the distribution is negatively skewed, then the:
The first four moments about the mean of distribution are 0, μ 2, 0.7 and 18.75. If the distribution is mesokurtic, the value of μ 2, is
If Mean > Median > Mode, the distribution is:
