$6(8x + 25) - 70 = 5(8x + 25)$
We are asked to find the value of x in the given equation:
$6(8x + 25) - 70 = 5(8x + 25)$
Distribute the constants on both sides of the equation:
$6 \times 8x + 6 \times 25 - 70 = 5 \times 8x + 5 \times 25$
$48x + 150 - 70 = 40x + 125$
Combine the constant terms on the left side:
$48x + 80 = 40x + 125$
To solve for x, we need to gather all terms involving x on one side and the constant terms on the other side.
Subtract 40x from both sides:
$48x - 40x + 80 = 40x - 40x + 125$
$8x + 80 = 125$
Subtract 80 from both sides:
$8x + 80 - 80 = 125 - 80$
$8x = 45$
Divide both sides by 8 to find the value of x:
$x = \frac{45}{8}$
Convert the improper fraction to a mixed number. Divide 45 by 8:
Therefore, the value of x is:
$x = 5\frac{5}{8}$
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