The problem asks us to find a specific number. Let this unknown number be represented by the variable 'x'.
We are given that four-fifth of the number ('x') is 4 more than its three-fourth. We can write this relationship as an equation:
\(\frac{4}{5}x = \frac{3}{4}x + 4\)
To find the value of 'x', we need to isolate it. First, bring the terms involving 'x' to one side of the equation:
\(\frac{4}{5}x - \frac{3}{4}x = 4\)
Find a common denominator for the fractions, which is 20:
\((\frac{4 \times 4}{5 \times 4})x - (\frac{3 \times 5}{4 \times 5})x = 4\)
\(\frac{16}{20}x - \frac{15}{20}x = 4\)
Combine the fractions:
\(\frac{16 - 15}{20}x = 4\)
\(\frac{1}{20}x = 4\)
Now, solve for 'x' by multiplying both sides by 20:
\(x = 4 \times 20\)
\(x = 80\)
Let's check if the number 80 satisfies the condition:
The difference is indeed 4, confirming our answer.
The sum of three fractions A, B, and C, A > B > C, is \(\frac{121}{60}\) . When C is divided by B, the resulting fraction is \(\frac{9}{10}\) , which exceeds A by \(\frac{3}{20}\) . What is the difference between B and C?
7 is added to a certain number and the sum is multiplied by 5. The product is then divided by 3 and 4 is subtracted from the quotient. If the result comes to 16, then what is the original number?
If the measure of one angle of a right triangle is 30° more than the measure of the smallest angle, then the measure of the smallest angle is:
A man has equal number of five, ten and twenty rupee notes amounting to Rs. 385. Find the total number of notes?
The sum of three consecutive number is 126. Find the highest number?