Find the third proportional to 24 and 60.
150
The question asks us to find the third proportional to the numbers 24 and 60. Understanding the concept of proportionality is key here.
When three numbers, say \(a\), \(b\), and \(c\), are in continued proportion, it means that the ratio of the first to the second is equal to the ratio of the second to the third. This can be written as:
\[\frac{a}{b} = \frac{b}{c}\]
In this continued proportion, \(a\) is the first proportional, \(b\) is the mean proportional, and \(c\) is the third proportional.
In our problem, the two given numbers are 24 and 60. If 24, 60, and the unknown third proportional (\(c\)) are in continued proportion, then:
So, we can set up the proportion as follows:
\[\frac{24}{60} = \frac{60}{c}\]
To find the value of \(c\), we can use cross-multiplication. This involves multiplying the numerator of the first ratio by the denominator of the second ratio and setting it equal to the product of the denominator of the first ratio and the numerator of the second ratio.
Applying cross-multiplication to our equation:
\[24 \times c = 60 \times 60\]
Now, we simplify the equation:
\[24c = 3600\]
To isolate \(c\), we divide both sides of the equation by 24:
\[c = \frac{3600}{24}\]
Let's perform the division:
\[c = \frac{3600}{24} = \frac{1800}{12} = \frac{900}{6} = \frac{450}{3} = 150\]
So, the third proportional to 24 and 60 is 150.
We can verify this by checking if 24, 60, and 150 are in continued proportion:
\[\frac{24}{60} = \frac{24 \div 12}{60 \div 12} = \frac{2}{5}\]
\[\frac{60}{150} = \frac{60 \div 30}{150 \div 30} = \frac{2}{5}\]
Since both ratios are equal to \(\frac{2}{5}\), the numbers 24, 60, and 150 are indeed in continued proportion, and 150 is the correct third proportional.
| Concept | Definition | Example |
|---|---|---|
| Ratio | A comparison of two quantities of the same kind by division. | The ratio of 10 to 5 is \(\frac{10}{5} = 2\) or 2:1. |
| Proportion | An equality of two ratios. If \(\frac{a}{b} = \frac{c}{d}\), then \(a, b, c, d\) are in proportion. | \(\frac{2}{4} = \frac{3}{6}\), so 2, 4, 3, 6 are in proportion. |
| Continued Proportion | When the ratio of the first term to the second is equal to the ratio of the second term to the third, and so on. \(\frac{a}{b} = \frac{b}{c} = \frac{c}{d} = ...\) | 3, 6, 12 are in continued proportion because \(\frac{3}{6} = \frac{1}{2}\) and \(\frac{6}{12} = \frac{1}{2}\). |
| Mean Proportional | For two numbers \(a\) and \(c\), the mean proportional \(b\) satisfies \(\frac{a}{b} = \frac{b}{c}\), which means \(b^2 = ac\), so \(b = \sqrt{ac}\). | The mean proportional between 4 and 9 is \(\sqrt{4 \times 9} = \sqrt{36} = 6\). |
| Third Proportional | For two numbers \(a\) and \(b\), the third proportional \(c\) satisfies \(\frac{a}{b} = \frac{b}{c}\). | For 24 and 60, the third proportional \(c\) satisfies \(\frac{24}{60} = \frac{60}{c}\). |
| Fourth Proportional | For three numbers \(a, b, c\), the fourth proportional \(d\) satisfies \(\frac{a}{b} = \frac{c}{d}\). | The fourth proportional to 1, 2, and 3 is \(d\) such that \(\frac{1}{2} = \frac{3}{d}\), so \(d = 6\). |
Proportionality is a fundamental concept in mathematics that describes how two quantities are related. Beyond continued proportion, there are other important types of proportionality, such as direct proportion and inverse proportion.
Understanding these different types of proportionality helps in solving a wide range of problems in various fields, including physics, chemistry, economics, and everyday life.
What is the third proportional to 9 and 36?
What is the third proportional to 16 and 40?
When the same number is subtracted from each of 7, 9, 11 and 15, the resulting numbers are in proportion. The number subtracted is:
If L : M = 3 : 5 and M : N = 2 : 3, then N : L = ?
A. 2 : 1
B. 5 : 2
C. 3 : 2
D. 1 : 2
What is the third proportional to 16 and 24 ?