Find the smallest number divisible by 5, 10 and 15.
30
The smallest number divisible by 5, 10 and 15 is their LCM.
Prime factors: 5 = 5, 10 = 2 × 5, 15 = 3 × 5.
LCM = 2 × 3 × 5 = 30.
Hence, the answer is 30.
Similar Questions
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Important Questions from LCM and HCF
The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
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What is the least number which when divided by 12,20 and 24 leaves in each case a remainder of 8?
Which of the following is a pair of co-primes?
