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Question

Find the different term:

This question was previously asked in
SSC Stenographer 2025 Question Paper (06-Aug-2025) Shift 2
The correct answer is
90

Different Term Identification

The goal of this question is to identify which number in the list does not share a common mathematical property with the others. This requires analyzing the properties of each given number.

Number Options Analysis

The options provided are:

  • Option 1: 49
  • Option 2: 64
  • Option 3: 90
  • Option 4: 81

We will look for a pattern among these numbers.

Perfect Squares Pattern

A common pattern in such questions is whether the numbers are perfect squares. A perfect square is a number that results from multiplying an integer by itself.

  • 49: This number can be obtained by squaring the integer 7. Calculation: \(49 = 7 \times 7 = 7^2\). So, 49 is a perfect square.
  • 64: This number can be obtained by squaring the integer 8. Calculation: \(64 = 8 \times 8 = 8^2\). So, 64 is a perfect square.
  • 81: This number can be obtained by squaring the integer 9. Calculation: \(81 = 9 \times 9 = 9^2\). So, 81 is a perfect square.

Outlier: Number 90

Now, let's check the number 90 for the same property:

We need to determine if 90 is a perfect square.

  • Consider the squares of integers near the square root of 90.
  • We know that \(9^2 = 81\).
  • The next integer square is \(10^2 = 100\).
  • Since 90 falls between 81 and 100, it cannot be represented as the square of an integer (\(n^2\)).
  • Therefore, 90 is not a perfect square.

Term Conclusion

By analyzing the options, we found that 49, 64, and 81 are all perfect squares. The number 90 does not fit this pattern because it is not a perfect square. Consequently, 90 is the different term in the list.

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Important Questions from Classification

  1. Directions for the following 3 (three) items : consider the given information and answer the three items that follow. 

    A, B, C, D, E, F and G are Lecturers from different cities—Hyderabad, Delhi, Shillong, Kanpur, Chennai, Mumbai and Srinagar (not necessarily in the same order) who participated in a conference. Each one of them is specialized in a different subject, viz., Economics, Commerce, History, Sociology, Geography, Mathematics and Statistics (not necessarily in the same order). 

    Further 1. Lecturer from Kanpur is specialized in Geography 

    2. Lecturer D is from Shillong 

    3. Lecturer C from Delhi is specialized in Sociology 

    4. Lecturer B is specialized in neither History nor Mathematics 

    5. Lecturer A who is specialized in Economics does not belong to Hyderabad 

    6. Lecturer F who is specialized in Commerce belongs to Srinagar 

    7. Lecturer G who is specialized in Statistics belongs to Chennai 

    Who is specialized in Geography?

  2. A, B, C, D, E, F and G are Lecturers from different cities—Hyderabad, Delhi, Shillong, Kanpur, Chennai, Mumbai and Srinagar (not necessarily in the same order) who participated in a conference. Each one of them is specialized in a different subject, viz., Economics, Commerce, History, Sociology, Geography, Mathematics and Statistics (not necessarily in the same order). 

    Further 1. Lecturer from Kanpur is specialized in Geography 

    2. Lecturer D is from Shillong 

    3. Lecturer C from Delhi is specialized in Sociology 

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    Further 1. Lecturer from Kanpur is specialized in Geography 

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