Fifty observations of production operation revealed a mean cycle time of 10 min. The worker was evaluated to be performing at 90% efficiency. Assuming the allowances to be 10% of the normal time, the standard time (in minutes) for the job is
The question asks us to determine the standard time for a production job, given the mean cycle time, worker efficiency, and allowances.
To find the standard time, we first need to calculate the normal time, and then add the allowances to the normal time.
Normal Time is calculated using the formula:
\(\text{Normal Time} = \text{Observed Time} \times \text{Performance Rating}\)
Given:
Calculation:
\(\text{Normal Time} = 10 \text{ min} \times 0.90\)
\(\text{Normal Time} = 9 \text{ min}\)
Standard Time is calculated by adding allowances to the Normal Time. The allowances are 10% of the Normal Time.
\(\text{Allowances Amount} = 10\% \text{ of Normal Time}\)
\(\text{Allowances Amount} = 0.10 \times 9 \text{ min}\)
\(\text{Allowances Amount} = 0.9 \text{ min}\)
Now, add the allowances to the normal time:
\(\text{Standard Time} = \text{Normal Time} + \text{Allowances Amount}\)
\(\text{Standard Time} = 9 \text{ min} + 0.9 \text{ min}\)
\(\text{Standard Time} = 9.9 \text{ min}\)
Alternatively, we can use the formula:
\(\text{Standard Time} = \text{Normal Time} \times (1 + \text{Allowance Percentage as Decimal})\)
\(\text{Standard Time} = 9 \text{ min} \times (1 + 0.10)\)
\(\text{Standard Time} = 9 \text{ min} \times 1.10\)
\(\text{Standard Time} = 9.9 \text{ min}\)
| Parameter | Value |
|---|---|
| Observed Time (Mean Cycle Time) | 10 min |
| Performance Rating (Efficiency) | 90% (0.90) |
| Normal Time | \(10 \times 0.90 = 9\) min |
| Allowances (% of Normal Time) | 10% (0.10) |
| Allowances Amount | \(0.10 \times 9 = 0.9\) min |
| Standard Time | \(9 + 0.9 = 9.9\) min |
The calculated standard time for the job is 9.9 minutes.
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