Only three people have exams between O and S. Only three people have exams between G and J. T has an exam on some day before R and on some day after M. Only J has an exam after S.
Who has an exam on Thursday?
The problem requires determining the exam schedule for seven people (G, J, M, O, R, S, T) from Monday to Sunday using given clues, and identifying who has an exam on Thursday.
Deductive Reasoning for Schedule
- There are 7 distinct people and 7 days (Monday to Sunday).
- Clue 4: "Only J has an exam after S." This implies J is the last person (Sunday), and S is the second to last (Saturday).
- J = Sunday
- S = Saturday
- Clue 1: "Only three people have exams between O and S." With S on Saturday, O must be on Monday to have three people (Tue, Wed, Thu) between them.
- O = Monday
- Schedule: O (Mon), [P1] (Tue), [P2] (Wed), [P3] (Thu), [P4] (Fri), S (Sat), J (Sun).
- Clue 2: "Only three people have exams between G and J." With J on Sunday, G must be on Wednesday to have three people (Thu, Fri, Sat) between them.
- G = Wednesday
- Schedule: O (Mon), [P1] (Tue), G (Wed), [P2] (Thu), [P3] (Fri), S (Sat), J (Sun).
- Clue 3: "T has an exam ... before R and ... after M." This translates to the order M < T < R.
- Remaining people: M, T, R. Remaining days: Tuesday, Thursday, Friday.
- The only placement satisfying M < T < R is M=Tuesday, T=Thursday, R=Friday.
Exam Schedule Determined
| Day | Person |
|---|---|
| Monday | O |
| Tuesday | M |
| Wednesday | G |
| Thursday | T |
| Friday | R |
| Saturday | S |
| Sunday | J |
Thursday Exam Determined
According to the final schedule, T has the exam on Thursday.
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