How many numbers arc there between 99 and 1000 such that the digit 8 occupies the units place?
90
Numbers between 99 and 1000 are 100 to 999, i.e. all three digit numbers. Now, for 100 to 200: 8 will come at the unit’s place 10 times, i.e. 108, 118, 128…. 198. Similar will be the case with number sets of 201-300, 301-400 etc. Hence, the number of times that 8 will come at unit’s place between 99 and 1000 = 10 × 9 = 90
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