Exam Scheduling Logic Puzzle Solution
This solution determines the number of people with exams between A and D based on the given weekly scheduling constraints.
Analyzing the Constraints
- Seven people (A, B, C, D, S, T, U) have exams on separate days, Monday through Sunday.
- Fixed placements: S is on Thursday, U is on Saturday.
- Adjacent placements: T is immediately before B, and D is immediately after B. This creates a fixed TBD sequence.
- Order constraint: C's exam day precedes A's exam day.
Constructing the Weekly Schedule
We build the schedule logically:
- Initial layout: Mon, Tue, Wed, Thu, Fri, Sat, Sun.
- Place fixed exams: S on Thursday, U on Saturday. The week currently looks like: \(_ _ _ S _ U _\)
- Place the TBD sequence: This requires three consecutive empty slots. The only available consecutive slots are Monday, Tuesday, Wednesday. Thus:
- Monday: T
- Tuesday: B
- Wednesday: D
- Place remaining people (A, C): The remaining days are Friday and Sunday. Applying the constraint that C must be scheduled before A, we get:
- Friday: C
- Sunday: A
Final Exam Schedule
| Mon | Tue | Wed | Thu | Fri | Sat | Sun |
| T | B | D | S | C | U | A |
Determining Exams Between A and D
From the schedule, identify the exam days for A and D:
- A's exam is on Sunday.
- D's exam is on Wednesday.
The days that fall strictly between Wednesday and Sunday are Thursday, Friday, and Saturday.
The individuals scheduled on these days are:
- Thursday: S
- Friday: C
- Saturday: U
Counting these individuals, there are 3 people with exams between A and D.
Similar Questions
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Only three people have exams between O and S. Only three people have exams between G and J. T has an exam on some day before R and on some day after M. Only J has an exam after S.
Who has an exam on Thursday?
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