Die I has 4 red and 2 white faces and die II has 2 red and 4 white faces. A coin is flipped once. If head appears, the game continues by flipping die I, and if tail appears, then die II is used. The probability of getting a red face at any throw is:
1/2
We first calculate the probability of getting a red face for each die. For Die I, the probability of getting a red face is 4/6 (since there are 4 red faces out of 6 total faces). For Die II, the probability of getting a red face is 2/6. Since the coin flip determines which die is used, we calculate the total probability as follows:
Probability of getting a red face = (1/2 * 4/6) + (1/2 * 2/6) = (1/2 * 2/3) + (1/2 * 1/3) = 1/2.
Hence, the correct answer is 1/2.
If A and B are two events such that P(A∪B) = 3/4 P(A∩B)
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