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Question

Consider the following statements in respect of the function y = [x], x ∈ (-1, 1) where [.] is the greatest integer function:

1. Its derivative is 0 at x = 0.5

2. It is continuous at x = 0

Which of the above statements is/are correct?

This question was previously asked in
NDA I 2022 GAT Previous Year Paper (10-Apr-2022)
The correct answer is

1 only

Understanding the Greatest Integer Function \(y = [x]\)

The question asks us to analyze the properties of the function \(y = [x]\) within the interval \(x \in (-1, 1)\). The notation \([x]\) represents the greatest integer less than or equal to \(x\). Let's define the function explicitly for the given interval:

  • For \(x\) such that \(-1 < x < 0\), the greatest integer less than or equal to \(x\) is \(-1\). So, \(y = [x] = -1\).
  • For \(x\) such that \(0 \le x < 1\), the greatest integer less than or equal to \(x\) is \(0\). So, \(y = [x] = 0\).

We need to evaluate two statements about this function.

Analyzing Statement 1: Derivative at \(x = 0.5\)

Statement 1 says: Its derivative is 0 at \(x = 0.5\).

Let's consider the function \(y = [x]\) in the neighborhood of \(x = 0.5\). The value \(x = 0.5\) falls within the interval \(0 \le x < 1\). In this entire interval, the function is defined as \(y = [x] = 0\).

So, for any value of \(x\) slightly less than or slightly greater than \(0.5\) (as long as it stays within \(0 \le x < 1\)), the function value is a constant, \(0\).

The derivative of a constant function is always 0. Since the function \(y = [x]\) is a constant \(0\) in an open interval around \(x = 0.5\), its derivative at \(x = 0.5\) is 0.

Mathematically, the derivative at \(x=0.5\) is given by the limit: \[ f'(0.5) = \lim_{h \to 0} \frac{f(0.5+h) - f(0.5)}{h} \] For small values of \(h\) (positive or negative) such that \(0 \le 0.5+h < 1\), we have \(f(0.5+h) = [0.5+h] = 0\), and \(f(0.5) = [0.5] = 0\). \[ f'(0.5) = \lim_{h \to 0} \frac{0 - 0}{h} = \lim_{h \to 0} \frac{0}{h} = 0 \]

Therefore, Statement 1 is correct.

Analyzing Statement 2: Continuity at \(x = 0\)

Statement 2 says: It is continuous at \(x = 0\).

For a function to be continuous at a point \(x=c\), three conditions must be met:

  1. The function must be defined at \(x=c\).
  2. The limit of the function as \(x\) approaches \(c\) must exist (\(\lim_{x \to c} f(x)\) exists). This means the left-hand limit and the right-hand limit must be equal.
  3. The limit must be equal to the function value: \(\lim_{x \to c} f(x) = f(c)\).

Let's check these conditions for \(y = [x]\) at \(x = 0\):

  • Condition 1: Function defined at \(x=0\). For \(x=0\), \(y = [0] = 0\). The function is defined at \(x=0\).
  • Condition 2: Limit as \(x\) approaches \(0\). We need to check the left-hand limit (LHL) and the right-hand limit (RHL).
    • Left-hand limit (\(x \to 0^-\)): As \(x\) approaches \(0\) from values less than \(0\) (e.g., \(-0.1, -0.01, \dots\)), within the interval \((-1, 1)\), the function value is \(y = [x] = -1\). \[ \lim_{x \to 0^-} [x] = -1 \]
    • Right-hand limit (\(x \to 0^+\)): As \(x\) approaches \(0\) from values greater than \(0\) (e.g., \(0.1, 0.01, \dots\)), within the interval \((-1, 1)\), the function value is \(y = [x] = 0\). \[ \lim_{x \to 0^+} [x] = 0 \]
    Since the LHL (\(-1\)) is not equal to the RHL (\(0\)), the limit \(\lim_{x \to 0} [x]\) does not exist.

Because the limit does not exist, the function is not continuous at \(x=0\). The third condition (limit equals function value) also cannot be met.

Therefore, Statement 2 is incorrect.

Conclusion

Based on our analysis:

  • Statement 1: Its derivative is 0 at \(x = 0.5\) - Correct.
  • Statement 2: It is continuous at \(x = 0\) - Incorrect.

Only Statement 1 is correct.

Statement Analysis Correctness
1. Derivative at \(x=0.5\) is 0 Function is \(y=0\) near \(x=0.5\). Derivative of a constant is 0. Correct
2. Continuous at \(x=0\) LHL at \(x=0\) is \(-1\). RHL at \(x=0\) is \(0\). LHL \(\ne\) RHL. Limit does not exist. Incorrect

Revision Table: Key Concepts

Concept Description Relevance to Question
Greatest Integer Function \([x]\) Returns the largest integer less than or equal to \(x\). Jumps at integer values. The function being analyzed. Its definition is key to determining behavior.
Derivative of a Function Measures the instantaneous rate of change. For constant functions, it's 0. Used to check Statement 1 at a non-integer point.
Continuity at a Point Function must be defined, limit must exist (LHL=RHL), and limit must equal function value. Used to check Statement 2 at an integer point (where jumps occur).
Left-Hand Limit (LHL) Limit as \(x\) approaches a point from values less than the point. Crucial for checking continuity at integer points for step functions like \([x]\).
Right-Hand Limit (RHL) Limit as \(x\) approaches a point from values greater than the point. Crucial for checking continuity at integer points for step functions like \([x]\).

Additional Information about Greatest Integer Function

The greatest integer function, also known as the floor function, has several important properties:

  • Domain: All real numbers (\(\mathbb{R}\)).
  • Range: All integers (\(\mathbb{Z}\)).
  • Graph: The graph consists of a series of horizontal line segments. It has 'jumps' at every integer value of \(x\).
  • Discontinuity: The function is discontinuous at every integer value of \(x\). This is because the left-hand limit and the right-hand limit are different at integers.
  • Continuity: The function is continuous at all non-integer values of \(x\).
  • Differentiability: The derivative exists and is \(0\) at all non-integer values of \(x\), because the function is constant in a small interval around any non-integer point.
  • Non-Differentiability: The function is not differentiable at any integer value of \(x\) because it is discontinuous at these points.

In the given problem, \(x=0.5\) is a non-integer, so the derivative exists and is 0. The point \(x=0\) is an integer, where the function is discontinuous.

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