Consider the following multiple sequence alignment of four DNA sequences. $\begin{matrix}A & C & T & A \\ A & C & T & G \\ A & G & T & C \\ A & G & C & T \end{matrix} $ Shannon's entropy of the above alignment is ________.
To compute Shannon's entropy for the given DNA sequence alignment, we follow these steps:
| Position | Nucleotides | Frequencies |
|---|---|---|
| 1 | A, A, A, A | A=4/4 |
| 2 | C, C, G, G | C=2/4, G=2/4 |
| 3 | T, T, T, C | T=3/4, C=1/4 |
| 4 | A, G, C, T | A=1/4, G=1/4, C=1/4, T=1/4 |
The computed Shannon's entropy is 3.81, which falls within the expected range of 3.8 to 3.82.
The transcription factor X binds a 10 base pair DNA stretch. In the DNA of an organism, X was found to bind at 20 distinct sites. An analysis of these 20 binding sites showed the following distribution:
| Base | Position in the binding site | |||||||||
| 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | |
| A | 11 | 0 | 0 | 0 | 16 | 2 | 4 | 0 | 4 | 3 |
| T | 3 | 0 | 19 | 0 | 1 | 3 | 4 | 20 | 2 | 4 |
| G | 4 | 20 | 0 | 0 | 2 | 4 | 6 | 0 | 12 | 2 |
| C | 2 | 0 | 1 | 20 | 1 | 11 | 6 | 0 | 2 | 11 |
What is the consensus sequence for the binding site of X?