All Exams Test series for 1 year @ ₹349 only
Question

Consider the following in respect of inverse circular functions :
I. \(\sin^{-1}(-x) = -\sin^{-1} x\)
II. \(\cos^{-1}(-x) = \cos^{-1} x\)
III. \(\tan^{-1}(-x) = \pi - \tan^{-1} x\)
IV. \(\cot^{-1}(-x) = \pi - \cot^{-1} x\)
How many of the above are correct ?

This question was previously asked in
NDA 1 2026 GAT Question Paper (12-Apr-2026)
The correct answer is
Two

Inverse Circular Functions Properties Analysis

This question asks to identify the correct statements among the given properties of inverse circular functions. We need to verify each statement.

Statement I: \(\sin^{-1}(-x) = -\sin^{-1} x\)

The inverse sine function, \(\sin^{-1}(x)\), is an odd function. This means it satisfies the property \(\sin^{-1}(-x) = -\sin^{-1} x\) for all \(x\) in its domain, which is [-1, 1]. Therefore, statement I is correct.

Statement II: \(\cos^{-1}(-x) = \cos^{-1} x\)

The inverse cosine function, \(\cos^{-1}(x)\), is neither even nor odd. The correct identity involving \(-x\) is \(\cos^{-1}(-x) = \pi - \cos^{-1} x\) for \(x \in [-1, 1]\). The given statement incorrectly equates \(\cos^{-1}(-x)\) to \(\cos^{-1} x\). Therefore, statement II is incorrect.

Statement III: \(\tan^{-1}(-x) = \pi - \tan^{-1} x\)

The inverse tangent function, \(\tan^{-1}(x)\), is an odd function. It satisfies the property \(\tan^{-1}(-x) = -\tan^{-1} x\) for all \(x\) in its domain, which is \(\mathbb{R}\). The given statement is incorrect. Therefore, statement III is incorrect.

Statement IV: \(\cot^{-1}(-x) = \pi - \cot^{-1} x\)

The inverse cotangent function, \(\cot^{-1}(x)\), satisfies the property \(\cot^{-1}(-x) = \pi - \cot^{-1} x\) for all \(x\) in its domain, which is \(\mathbb{R}\). This property is similar to that of \(\cos^{-1}(x)\). Therefore, statement IV is correct.

Summary of Correct Statements

  • Statement I is correct.
  • Statement IV is correct.

Out of the four given statements, exactly two statements (I and IV) are correct.

Thus, the number of correct statements is Two.

Was this answer helpful?

Similar Questions

  1. What is 2 cot \(\left(\frac{1}{2} \cos ^{-1} \frac{\sqrt{5}}{3}\right)\) equal to ?

  2. The equation \({\tan ^{ - 1}}\left( {1 + {\rm{x}}} \right) + {\tan ^{ - 1}}\left( {1 - {\rm{x}}} \right) = \frac{{\rm{\pi }}}{2}\) is satisfied by

  3. What is tan −1 cot(cosec −1  2) equal to ?
  4. The equation \(sin^{-1}x-cos^{-1}x=\frac{\pi}{6}\) has

  5. What is \(\tan \left\{ 2{{\tan }^{-1}}\left( \frac{1}{3} \right) \right\}\) equal to?

  6. What is the value of \({\sin ^{ - 1}}\frac{4}{5} + {\sec ^{ - 1}}\frac{5}{4} - \frac{\pi }{2}?\)

  7. If \({\sin ^{ - 1}}\frac{{2p}}{{1 + p2}} - {\cos ^{ - 1}}\frac{{1 - {q^2}}}{{1 + {q^2}}} = {\tan ^{ - 1}}\frac{{2x}}{{1 - {x^2}}}\) , then what is x equal to?

  8. Consider the following values of x:

    1) 8

    2) -4

    3)  \(\frac 16\)

    4)  \(- \frac{1}{4}\)

    Which of the above values of x is/are the solution(s) of the equation

    \({\tan ^{ - 1}}\left( {2x} \right) + {\tan ^{ - 1}}\left( {3x} \right) = \frac{\pi }{4}?{\rm{\;}}\)

  9. What is \(\tan ^{- 1}\left( {\frac{1}{4}} \right) + {\tan ^{ - 1}}\left( {\frac{3}{5}} \right)\) equal to?

  10. Let the equation sec x.cosec x = p have a solution, where p is a positive real number. What should be the smallest value of p?


Important Questions from Inverse Trigonometric Functions

  1. What is 2 cot \(\left(\frac{1}{2} \cos ^{-1} \frac{\sqrt{5}}{3}\right)\) equal to ?

  2. The principal value of sin−1\(\frac{1}{\sqrt{2}}\) is equal to which of the following?

  3. The imaginary part of log sin (x + iy) is:

  4. The value of \({\tan ^{ - 1}}\left( {\frac{1}{2}} \right) + {\tan ^{ - 1}}\left( {\frac{1}{3}} \right)\) is

  5. The function \(f(x) = \sqrt {\cos (\sin x)} + {\sin ^{ - 1}}\left( {\frac{{1 + {x^2}}}{{2x}}} \right)\) is defined for

Need Expert Advice?
Upcoming Exams
NDA
September 13, 2026
CDS
September 13, 2026
Test Series
NDA img
Defence
NDA 2026 Mock Test Series (Latest Pattern)
501 Tests 1 Tests Free
770 Attempts
4.7(129)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App