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Question

Consider a parallel combination of 2 resistors with resistances 4 (0 800 6 0 . The equivalent resistance of the circuit is:

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is

\(2.4 \ \Omega\)

To find the equivalent resistance of a parallel combination of resistors, we use the formula:

\[ \frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} \]

Given \( R_1 = 4 \ \Omega \) and \( R_2 = 6 \ \Omega \), substitute these values into the formula:

\[ \frac{1}{R_{\text{eq}}} = \frac{1}{4} + \frac{1}{6} \]

To add these fractions, find a common denominator. The least common multiple of 4 and 6 is 12:

\[ \frac{1}{R_{\text{eq}}} = \frac{3}{12} + \frac{2}{12} = \frac{5}{12} \]

Now, take the reciprocal to find \( R_{\text{eq}} \):

\[ R_{\text{eq}} = \frac{12}{5} = 2.4 \ \Omega \]

The equivalent resistance of the parallel circuit is \(\boxed{2.4 \ \Omega}\).

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