The ration of the number of girls and boys in a school is 8 : 7. If the percentage increase in the number of girls and boys is 10% and 20% respectively, what will be the new ratio?
22 : 21
The problem asks us to find the new ratio of girls and boys in a school after their numbers increase by certain percentages. We are given the initial ratio and the percentage increase for each group.
The initial ratio of the number of girls to the number of boys in the school is given as 8 : 7.
We can represent the initial number of girls and boys using a common variable. Let the common multiplier be \(x\).
The number of girls increases by 10%.
Increase in girls = \(10\%\) of initial girls
Increase in girls = \(\frac{10}{100} \times 8x = \frac{1}{10} \times 8x = \frac{8x}{10}\)
The number of boys increases by 20%.
Increase in boys = \(20\%\) of initial boys
Increase in boys = \(\frac{20}{100} \times 7x = \frac{1}{5} \times 7x = \frac{7x}{5}\)
To make calculations easier, we can express the increase in boys with the same denominator as girls:
Increase in boys = \(\frac{7x}{5} = \frac{7x \times 2}{5 \times 2} = \frac{14x}{10}\)
The new number of girls is the initial number plus the increase.
New number of girls = Initial girls + Increase in girls
New number of girls = \(8x + \frac{8x}{10} = \frac{80x}{10} + \frac{8x}{10} = \frac{80x + 8x}{10} = \frac{88x}{10}\)
The new number of boys is the initial number plus the increase.
New number of boys = Initial boys + Increase in boys
New number of boys = \(7x + \frac{14x}{10} = \frac{70x}{10} + \frac{14x}{10} = \frac{70x + 14x}{10} = \frac{84x}{10}\)
The new ratio of girls to boys is the new number of girls divided by the new number of boys.
New Ratio = New number of girls : New number of boys
New Ratio = \(\frac{88x}{10} : \frac{84x}{10}\)
We can multiply both sides of the ratio by 10 to remove the denominator:
New Ratio = \(88x : 84x\)
Since \(x\) is a common factor (assuming \(x \neq 0\), as the number of students cannot be zero), we can cancel \(x\) from both sides:
New Ratio = \(88 : 84\)
To simplify the ratio \(88 : 84\), we need to find the greatest common divisor (GCD) of 88 and 84 and divide both numbers by it.
The greatest common divisor of 88 and 84 is 4.
Divide both parts of the ratio by 4:
\(88 \div 4 = 22\)
\(84 \div 4 = 21\)
The simplified new ratio is 22 : 21.
| Item | Initial Number (using \(x\)) | Percentage Increase | Increase Amount | New Number |
|---|---|---|---|---|
| Girls | \(8x\) | 10% | \(\frac{8x}{10}\) | \(\frac{88x}{10}\) |
| Boys | \(7x\) | 20% | \(\frac{14x}{10}\) | \(\frac{84x}{10}\) |
New Ratio = \(\frac{88x}{10} : \frac{84x}{10} = 88 : 84\)
Simplifying \(88 : 84\) by dividing by GCD(88, 84) = 4 gives \(22 : 21\).
Thus, the new ratio of girls and boys in the school will be 22 : 21.
Ratio problems often involve understanding how quantities relate to each other. A ratio like \(a:b\) means that for every \(a\) units of one quantity, there are \(b\) units of another. Percentage increase is calculated on the original amount, and the increased amount is added to the original to find the new total.
When dealing with ratios and percentage changes, it's crucial to apply the percentage change to the specific quantity it relates to (girls or boys in this case) based on their initial proportion. The common multiplier (\(x\)) used in this problem helps maintain the original ratio while allowing for calculation of absolute or proportional increases. Simplifying the final ratio is a standard step to present it in its most concise form.
The cheapest means of transport is:
The property of Catenation is most readily predominant in:
Which newspaper edited by Bal Gangadhar Tilak, was one of the strongest critics of the British rule?
Which of the following is NOT a cause of food and water contamination?
Select the most appropriate option to fill in the blank.
This case is limited to state _______.