Consider a journey by a car represented by the graph given below in three parts A, B and C. The speed of the car in these parts is Va, Vb and Vc, respectively: Which one of the following is correct in this case?
Vb > Va > Vc
A distance-time graph is a powerful tool used to represent the motion of an object. In such a graph, the distance traveled by the object is plotted on the vertical axis (y-axis), and time taken is plotted on the horizontal axis (x-axis).
The speed of an object moving at a constant velocity is given by the change in distance divided by the change in time. On a distance-time graph, the speed is represented by the slope of the line segment during a particular interval.
The formula for slope ($m$) of a line passing through points $(x_1, y_1)$ and $(x_2, y_2)$ is given by:
\(m = \frac{y_2 - y_1}{x_2 - x_1}\)
In a distance-time graph, if distance is on the y-axis and time on the x-axis, the slope is:
\(\text{Slope} = \frac{\text{Change in Distance}}{\text{Change in Time}}\)
This is exactly the definition of speed. Therefore, the slope of the line segment in a distance-time graph represents the speed of the object during that time interval.
Let's analyze the given graph which represents a car journey in three parts: A, B, and C. We need to compare the speeds \(V_a\), \(V_b\), and \(V_c\) in these respective parts.
We will visually inspect the slope of the line segments in parts A, B, and C to determine the relative speeds.
Part A: The line segment A starts from the origin and moves upwards and to the right. It has a positive slope, indicating the car is moving away from the starting point at a constant speed \(V_a\).
Part B: The line segment B starts where A ends and continues upwards and to the right. Compared to segment A, segment B is noticeably steeper. This indicates a higher slope than A, meaning the car is moving at a higher speed \(V_b\) in part B.
Part C: The line segment C starts where B ends and continues upwards and to the right. Compared to segment B, segment C is much less steep. Compared to segment A, segment C is also less steep. This indicates a lower slope than both A and B, meaning the car is moving at a lower speed \(V_c\) in part C.
Based on our analysis of the slopes:
Since speed is represented by the slope in a distance-time graph, we can conclude:
\(\text{Slope of B} > \text{Slope of A} > \text{Slope of C}\)
Therefore, the speeds are related as:
\(V_b > V_a > V_c\)
Comparing this relationship with the given options, we find that the correct relation between the speeds in parts A, B, and C of the car journey is \(V_b > V_a > V_c\).
| Feature on Graph | Represents | Interpretation for Motion |
|---|---|---|
| Slope of the line | Speed | Steeper slope = Higher speed Less steep slope = Lower speed Zero slope (horizontal) = Stationary |
| Straight line | Constant speed | Object moves at a steady rate |
| Curved line | Changing speed | Object is accelerating or decelerating |
| Slope becoming steeper | Increasing speed | Acceleration |
| Slope becoming less steep | Decreasing speed | Deceleration |
| Line returning towards time axis | Object returning to start point | Negative velocity (moving in opposite direction) |
Besides distance-time graphs, velocity-time graphs and acceleration-time graphs are also commonly used to describe motion. Each type of graph provides different information about the motion of an object.
Velocity-Time Graphs:
Acceleration-Time Graphs:
Understanding how to interpret the slope and area for each type of graph is crucial for analyzing motion.
Which one of the following is an example of Second Class Lever?
A uniform meter scale of mass 0.24 kg is made of steel. It is kept on two wedges, W1 and W2 , in a horizontal position. W1 is at a distance of 0.2 m from one of its ends, while W2 is at distance of 0.4 m from the other end. If the force on the scale is N1 due to W1 and N2 due to W2, then : (take g =10·0 m s-2
Rocket works on the principle of:
A rocket is launched to travel vertically upward with a constant velocity of 20 m/s. After travelling for 35 seconds, the rocket develops a snag and its fuel supply is cut off. The rocket then travels like a free body. The height achieved by it is:
According to Newton's third law of motion, mark the correct option.
1. Action and reaction act on different bodies and so they can be cancelled out.
2. The internal action and reaction forces between different parts of a body do, however, sum to zero.