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Question

Choose the correct expression for ion velocity in mass spectrometry:

This question was previously asked in
CUET PG 2026 Agri-Business Management Question Paper (25-Mar-2026) (Shift 2)
The correct answer is
$v = ((2.K.E)/m)^{0.5}$

Mass Spectrometry Ion Velocity Derivation

The velocity ($v$) of an ion in mass spectrometry is fundamentally linked to its kinetic energy ($K.E.$) and mass ($m$).

Kinetic Energy Equation

The basic physics formula for kinetic energy is:

$K.E. = \frac{1}{2}mv^2$

Deriving the Velocity Expression

To find the ion velocity ($v$), we rearrange the kinetic energy formula:

  1. Isolate $v^2$: Multiply the equation by 2 and divide by $m$.
  2. $v^2 = \frac{2 \times K.E.}{m}$
  3. Solve for $v$: Take the square root of both sides, which is equivalent to raising to the power of 0.5.
  4. $v = (\frac{2 \times K.E.}{m})^{0.5}$

This derived expression can be written in the format $v = ((2 \times K.E.) / m)^{0.5}$.

Evaluating Options

We compare this derived formula with the provided options:

  • Option 1: $v = ((2.K.E)/m)^{1.5}$ - The exponent (1.5) is incorrect.
  • Option 2: $v = ((2.K.E)/m)^{0.5}$ - This matches the derived formula for ion velocity.
  • Option 3: $v = ((2.K.E)/m)^2$ - The exponent (2) is incorrect.
  • Option 4: $v = ((K.E)/2.m)^{0.5}$ - The factor of 2 is incorrectly placed in the denominator.

Final Determination

Based on the derivation from the kinetic energy principle, the correct expression for ion velocity is $v = ((2 \times K.E.) / m)^{0.5}$.

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