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Most stable conformation of n-butane

This question was previously asked in
CUET PG 2026 Agri-Business Management Question Paper (25-Mar-2026) (Shift 2)
The correct answer is
Anti form

N-Butane Conformation Stability

Conformational analysis examines the relative energies of different spatial arrangements (conformations) of a molecule that arise from rotation around single bonds. For n-butane ($CH_3CH_2CH_2CH_3$), the rotation around the central C2-C3 bond leads to various conformations.

Energy Factors in N-Butane Conformations

The stability of these conformations depends on:

  • Torsional Strain: Energy cost due to eclipsing electron densities of bonds.
  • Steric Strain (or Van der Waals Strain): Repulsive interactions between non-bonded atoms or groups that are close to each other in space.

Analysis of N-Butane Conformations

The key conformations and their relative stability are:

  • Fully Eclipsed (0°): Highest energy due to maximum steric strain (methyl groups eclipsed) and torsional strain.
  • Gauche (approx. 60°): Lower energy than eclipsed forms. There is some steric strain between the two methyl groups, but less than in the fully eclipsed form.
  • Eclipsed (approx. 120°): Higher energy than gauche due to torsional strain and some eclipsing interactions between H and $CH_3$.
  • Anti (approx. 180°): Lowest energy conformation. The two methyl groups are positioned 180° apart, minimizing steric hindrance. Torsional strain is also minimized compared to eclipsed forms.

Conclusion on Stability

The Anti form is the most stable conformation of n-butane because it minimizes both torsional strain and, crucially, the steric repulsion between the bulky methyl groups.

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