Question
Calculate the oxidation number of ‘S’ in H2S2O7.
This question was previously asked in
SSC CGL 2024 (Tier-I) Previous Year Paper (17-Sep-2024) (Shift 3)
The correct answer is
6
\[\text{Let the oxidation number of sulfur be } x.\]\[\text{In } \mathrm{H_2S_2O_7}:\]\[\text{Hydrogen (H): } 2 \times (+1) = +2\]\[\text{Oxygen (O): } 7 \times (-2) = -14\]\[\text{Sulfur (S): } 2 \times x = 2x\]\[\text{Total oxidation number of the neutral compound = 0}\]\[2(+1) + 2x + 7(-2) = 0 \Rightarrow 2 + 2x - 14 = 0 \Rightarrow 2x - 12 = 0 \Rightarrow 2x = 12 \Rightarrow x = 6\]
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