The initial situation involves selling $50$ mangoes for $₹30$ with a $10\%$ loss.
We can write this as an equation:
$SP = 0.90 \times CP$
$₹30 = 0.90 \times CP$
Now, solve for $CP$:
$CP = \frac{₹30}{0.90} = \frac{300}{9} = \frac{100}{3}$
So, the Cost Price ($CP$) for $50$ mangoes is $₹\frac{100}{3}$.
The goal is to achieve a $20\%$ gain.
Calculate the target $SP$ for $50$ mangoes:
$SP_{target} = 1.20 \times CP$
$SP_{target} = 1.20 \times ₹\frac{100}{3} = \frac{12}{10} \times \frac{100}{3} = \frac{4}{10} \times 100 = ₹40$
Therefore, to gain $20\%$, $50$ mangoes must be sold for $₹40$.
We need to find out how many mangoes should be sold for $₹28$ to achieve the $20\%$ gain.
We know:
Let $x$ be the number of mangoes to be sold for $₹28$. We can use a proportion:
$\frac{\text{Number of Mangoes}}{\text{Selling Price}} = \text{constant}$
$\frac{50}{₹40} = \frac{x}{₹28}$
Solve for $x$:
$x = \frac{50 \times 28}{40} = \frac{5 \times 28}{4} = 5 \times 7 = 35$
Thus, $35$ mangoes should be sold for $₹28$ to gain $20\%$.
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