Let $C$ represent the cost price of one book and $S$ represent the selling price of one book.
The problem states that the selling price (SP) of 40 books is equal to the cost price (CP) of 28 books.
This can be written as an equation:
$ 40 \times S = 28 \times C $
From the equation, we can find the relationship between $S$ and $C$:
$ S = \frac{28}{40} C $
Simplify the fraction:
$ S = \frac{7}{10} C $
Since the selling price ($S$) is $\frac{7}{10}$ of the cost price ($C$), it means $S < C$. This indicates a loss.
The loss amount for one book is:
$ \text{Loss} = C - S = C - \frac{7}{10} C = \frac{10C - 7C}{10} = \frac{3}{10} C $
To find the loss percentage, we use the formula:
$ \text{Loss Percentage} = \left( \frac{\text{Loss}}{\text{Cost Price}} \right) \times 100 $
Substitute the values:
$ \text{Loss Percentage} = \left( \frac{\frac{3}{10} C}{C} \right) \times 100 $
$ \text{Loss Percentage} = \frac{3}{10} \times 100 $
$ \text{Loss Percentage} = 30\% $
Therefore, there is a loss of 30%.
By selling an article for Rs. 2,200, a profit of 10% is earned. If the same article is sold for Rs. 2,600, then what will be the gain percentage?
By selling an article for Rs. 640, a person loses 15% of its selling price. At what price (in Rs.) should he sell it to gain 15% on its cost price?
The selling prices of articles A and B are the same. A is sold at a profit of 28 percent and B is sold at a loss of 24 percent. If the total selling price of the both articles is Rs. 48640, then what is the cost price of A and B, respectively ?
The cost price of an article is Rs. 2800. Profit as a percentage of selling price is 20 percent. What is the actual profit (in Rs.) ?
A trader bought 640 kg of rice. He sold a part of rice at 20% profit and the rest at 5% loss. He earned a profit of 15% in the entire transaction. What is the quantity (in kg) of rice that he sold at 5% loss?