Let $C$ represent the cost price of one book and $S$ represent the selling price of one book.
The problem states that the selling price (SP) of 40 books is equal to the cost price (CP) of 28 books.
This can be written as an equation:
$ 40 \times S = 28 \times C $
From the equation, we can find the relationship between $S$ and $C$:
$ S = \frac{28}{40} C $
Simplify the fraction:
$ S = \frac{7}{10} C $
Since the selling price ($S$) is $\frac{7}{10}$ of the cost price ($C$), it means $S < C$. This indicates a loss.
The loss amount for one book is:
$ \text{Loss} = C - S = C - \frac{7}{10} C = \frac{10C - 7C}{10} = \frac{3}{10} C $
To find the loss percentage, we use the formula:
$ \text{Loss Percentage} = \left( \frac{\text{Loss}}{\text{Cost Price}} \right) \times 100 $
Substitute the values:
$ \text{Loss Percentage} = \left( \frac{\frac{3}{10} C}{C} \right) \times 100 $
$ \text{Loss Percentage} = \frac{3}{10} \times 100 $
$ \text{Loss Percentage} = 30\% $
Therefore, there is a loss of 30%.
Rohit buys 8 pens and 4 pencils for Rs. 2400. He sells pencils at a profit of 20 percent and pens at the loss of 10 percent. If his overall profit is Rs. 240, then what is the sum of the cost price of one pen and one pencil?
A man sells a car to his friend at the loss of 10 %; who in return sells it for Rs. 54000 making a profit of 20 %. What was the initial value of the car?
By selling a horse for Rs. 670, a tradesman would lose 5%. At what price must he sell it to gain 5%?
An article was sold at a loss of 24%. If it were sold for Rs. 1,596 more, then there would have been a gain of 18%, The cost price of the article is:
The cost price of an article is Rs.6,450. If it sold at a profit 16%, how much would be its selling price?