Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which pair does not belong to that group?
(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter-cluster.)
TB-ZF
Analyzing Alphabetical Letter Cluster Pairs
This question asks us to identify the letter-cluster pair that does not follow the same pattern as the others, based on the English alphabetical order. We need to examine the relationship between the letters within each pair and across the pairs.
Identifying the Pattern
Let's assign numerical positions to each letter based on the English alphabet (A=1, B=2, ..., Z=26).
We will analyze the relationship between the letters in each given pair. The key is to find a consistent rule that applies to three of the options.
Let's test the hypothesis that the difference between the first letter and the second letter within each pair is consistent (considering wrap-around for the alphabet).
Option 1: SA-PX
- Pair 1: SA
- Position of S = 19
- Position of A = 1
- Relationship: S is 18 positions after A. Or, thinking A to S is +18. Let's check the reverse: S (19) moving backward to A (1) involves passing Z (26). The difference S to A can be seen as \(1 - 19 = -18\). Wrapping around, this is equivalent to a difference of \(26 - 18 = 8\) positions forward from A to S, or considering the difference \(S \to P\), which is \(19 \to 16\), a difference of \(-3\).
- Pair 2: PX
- Position of P = 16
- Position of X = 24
- Relationship: X is 8 positions after P. The difference is \(24 - 16 = 8\). Let's check the difference \(P \to X\), which is \(16 \to 24\), a difference of \(+8\).
- Let's re-examine the pattern based on common logic puzzles: Find the offset between the first letter of the first pair and the first letter of the second pair, and similarly for the second letters.
- S (19) and P (16): Difference is \(19 - 16 = 3\).
- A (1) and X (24): Difference is \(1 - 24 = -23\). Wrapped around, \(1 \to 26 \to 25 \to 24\). This is a difference of \(-3\) (1 -> Z is -1, Z -> Y is -2, Y -> X is -3).
Option 2: TB-ZF
- Pair 1: TB
- Position of T = 20
- Position of B = 2
- Difference T to B: \(20 \to 2\). Wrapping around, this is \(20 \to 26\) (+6) and \(26 \to 2\) (+2), so \(+8\) positions forward? Or \(2 - 20 = -18\). Wrapped around, \(-18\) is equivalent to \(26 - 18 = 8\) forward. Let's check the difference from T to Z.
- Pair 2: ZF
- Position of Z = 26
- Position of F = 6
- Difference Z to F: \(26 \to 6\). Wrapping around, \(26 \to 1 \to 2 \to 3 \to 4 \to 5 \to 6\). This is \(+6\) positions forward. Or \(6 - 26 = -20\). Wrapped around, \(-20\) is equivalent to \(26 - 20 = 6\) forward.
- Checking the difference between corresponding letters:
- T (20) and Z (26): Difference is \(26 - 20 = +6\).
- B (2) and F (6): Difference is \(6 - 2 = +4\).
Option 3: LT-IQ
- Pair 1: LT
- Position of L = 12
- Position of T = 20
- Pair 2: IQ
- Position of I = 9
- Position of Q = 17
- Checking the difference between corresponding letters:
- L (12) and I (9): Difference is \(12 - 9 = 3\). Or \(9 - 12 = -3\).
- T (20) and Q (17): Difference is \(20 - 17 = 3\). Or \(17 - 20 = -3\).
Option 4: EM-BJ
- Pair 1: EM
- Position of E = 5
- Position of M = 13
- Pair 2: BJ
- Position of B = 2
- Position of J = 10
- Checking the difference between corresponding letters:
- E (5) and B (2): Difference is \(5 - 2 = 3\). Or \(2 - 5 = -3\).
- M (13) and J (10): Difference is \(13 - 10 = 3\). Or \(10 - 13 = -3\).
Conclusion: Finding the Odd Pair
We observed a pattern where the first letter of the second pair is 3 positions *before* the first letter of the first pair (considering wrap-around), and the second letter of the second pair is also 3 positions *before* the second letter of the first pair.
- SA-PX: S(19) to P(16) is -3. A(1) to X(24) is -3 (wrap-around). Fits.
- LT-IQ: L(12) to I(9) is -3. T(20) to Q(17) is -3. Fits.
- EM-BJ: E(5) to B(2) is -3. M(13) to J(10) is -3. Fits.
- TB-ZF: T(20) to Z(26) is +6. B(2) to F(6) is +4. Does NOT fit.
Therefore, the pair TB-ZF does not belong to the group because it does not follow the established alphabetical difference pattern of \(-3\) between corresponding letters.
Similar Questions
Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which pair does not belong to that group?
(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter cluster.)
Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which pair does not belong to that group?
(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter-cluster.)
Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which pair does not belong to that group?
(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter-cluster.)Based on the English alphabetical order, three of the following four letter-clusters are alike in a certain way and thus form a group. Which letter-cluster does not belong to that group?
(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter cluster.)Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which pair does not belong to that group?
(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter cluster.)
Based on the English alphabetical order, three of the following four letter-clusters are alike in a certain way and thus form a group. Which letter-cluster does not belong to that group?
(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter-cluster.)
Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which pair does not belong to that group?
(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter cluster.)
Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which pair does not belong to that group?
(Note: The odd one out is not based on the number of consonants/vowels or their position in the letter-cluster.)
- Based on the English alphabetical order, three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which letter-cluster pair DOES NOT belong to that group? (Note: The odd one out is not based on the number of consonants/vowels or their position in the letter-cluster.)
- Based on the English alphabetical order, three of the following four letter-clusters are alike in a certain way and thus form a group. Which letter-cluster DOES NOT belong to that group? (Note: The odd one out is not based on the number of consonants/vowels or their position in the letter-cluster.)
Important Questions from Classification
Directions for the following 3 (three) items : consider the given information and answer the three items that follow.
A, B, C, D, E, F and G are Lecturers from different cities—Hyderabad, Delhi, Shillong, Kanpur, Chennai, Mumbai and Srinagar (not necessarily in the same order) who participated in a conference. Each one of them is specialized in a different subject, viz., Economics, Commerce, History, Sociology, Geography, Mathematics and Statistics (not necessarily in the same order).
Further 1. Lecturer from Kanpur is specialized in Geography
2. Lecturer D is from Shillong
3. Lecturer C from Delhi is specialized in Sociology
4. Lecturer B is specialized in neither History nor Mathematics
5. Lecturer A who is specialized in Economics does not belong to Hyderabad
6. Lecturer F who is specialized in Commerce belongs to Srinagar
7. Lecturer G who is specialized in Statistics belongs to Chennai
Who is specialized in Geography?
A, B, C, D, E, F and G are Lecturers from different cities—Hyderabad, Delhi, Shillong, Kanpur, Chennai, Mumbai and Srinagar (not necessarily in the same order) who participated in a conference. Each one of them is specialized in a different subject, viz., Economics, Commerce, History, Sociology, Geography, Mathematics and Statistics (not necessarily in the same order).
Further 1. Lecturer from Kanpur is specialized in Geography
2. Lecturer D is from Shillong
3. Lecturer C from Delhi is specialized in Sociology
4. Lecturer B is specialized in neither History nor Mathematics
5. Lecturer A who is specialized in Economics does not belong to Hyderabad
6. Lecturer F who is specialized in Commerce belongs to Srinagar
7. Lecturer G who is specialized in Statistics belongs to Chennai
To which city does the Lecturer specialized in Economics belong?
A, B, C, D, E, F and G are Lecturers from different cities—Hyderabad, Delhi, Shillong, Kanpur, Chennai, Mumbai and Srinagar (not necessarily in the same order) who participated in a conference. Each one of them is specialized in a different subject, viz., Economics, Commerce, History, Sociology, Geography, Mathematics and Statistics (not necessarily in the same order).
Further 1. Lecturer from Kanpur is specialized in Geography
2. Lecturer D is from Shillong
3. Lecturer C from Delhi is specialized in Sociology
4. Lecturer B is specialized in neither History nor Mathematics
5. Lecturer A who is specialized in Economics does not belong to Hyderabad
6. Lecturer F who is specialized in Commerce belongs to Srinagar
7. Lecturer G who is specialized in Statistics belongs to Chennai
Who of the following belongs to Hyderabad?
In a school, there are five teachers A, B, C, D and E. A and B teach Hindi and English. C and B teach English and Geography. D and A teach Mathematics and Hindi. E and B teach History and French. Who teaches maximum numb, of subjects?
How many triangles are there in the given figure?
