At the time of short-circuit, the current in the circuit:
increases heavily.
Let's break down what happens during a short circuit and how it affects the current flowing through the electrical circuit. A short circuit is essentially an abnormal connection between two points of different potential (voltage) in a circuit, where the resistance between these points is very low or near zero. This low resistance allows a very large current to flow.
Ohm's Law is a fundamental principle in electrical circuits. It states that the voltage (V) across a resistor is directly proportional to the current (I) flowing through it, provided the temperature and other physical conditions remain constant. The relationship is given by the formula:
\(V = I \times R\)
Where:
We can rearrange Ohm's Law to solve for current:
\(I = \frac{V}{R}\)
This formula tells us that for a constant voltage source (like a battery or wall outlet), the current flowing through a circuit is inversely proportional to the resistance. If resistance increases, current decreases. If resistance decreases, current increases.
During a typical operation of an electrical device, there is a designed resistance in the circuit that limits the current flow to a safe and functional level. When a short circuit occurs, this resistance is bypassed or significantly reduced. The resistance becomes very, very low – ideally, it could be close to zero ohms, although in reality, there is always some small resistance.
Consider the formula \(I = \frac{V}{R}\). In a short circuit:
If the resistance \(R\) is very small, dividing the constant voltage \(V\) by a very small number results in a very large value for the current \(I\).
For example, if you have a 12V battery and a normal circuit has a resistance of 10 \(\Omega\), the current is \(I = \frac{12V}{10\Omega} = 1.2A\). If a short circuit reduces the resistance to just 0.1 \(\Omega\), the current becomes \(I = \frac{12V}{0.1\Omega} = 120A\). This is a huge increase in current.
Therefore, at the time of a short circuit, the current in the circuit increases heavily.
Let's look at the given options based on our understanding:
Based on Ohm's Law and the nature of a short circuit (very low resistance), the current increases heavily.
| Circuit Condition | Resistance (R) | Current (I = V/R) |
|---|---|---|
| Normal Operation | High (e.g., device resistance) | Normal level |
| Short Circuit | Very Low (close to 0) | Very High (increases heavily) |
| Term | Definition/Concept |
|---|---|
| Short Circuit | An abnormal low-resistance connection in a circuit. |
| Ohm's Law | \(V = I \times R\), relating voltage, current, and resistance. |
| Resistance (R) | Opposition to current flow. Lower resistance means more current for the same voltage. |
| Current (I) | Flow of electric charge. |
Short circuits are dangerous because the extremely high current can generate significant heat, potentially causing fires, damaging equipment, or leading to electric shock hazards. Electrical systems are typically protected by fuses or circuit breakers, which are designed to detect this surge in current and quickly interrupt the circuit, stopping the dangerous flow of electricity and preventing damage.
Understanding the relationship between voltage, current, and resistance, as described by Ohm's Law, is crucial for analyzing circuit behavior, especially in fault conditions like short circuits.
Which of the following statements are correct about the electrical resistance and resistivity of a wire?
1. Both quantities depend on the area of cross-section of the wire
2. Both depend on the temperature
3. Resistance of the wire is directly proportional to the resistivity of the wire
4. Resistivity of the wire is directly proportional to the length of the
wire
Select the correct answer using the code given below:
A circular coil of single turn has a resistance of 20 Ω. Which one of the following is the correct value for resistance between the ends of any diameter of the coil?
Which one of the following physical quantities does NOT affect the resistance of a cylindrical resistor?
Let us consider a copper wire having radius r and length l. Let its resistance be R. If the radius of another copper wire is 2r and the length is l/2 then the resistance of this wire will be
A fuse wire must be