Let the present age of Vanraj's son be represented by $S$ years.
We need to determine their ages 3 years prior to the present:
The problem states that the sum of their ages 3 years ago was 58 years.
Equation:
$(3S - 3) + (S - 3) + (S - 6) = 58$
Combine like terms to solve the equation for $S$:
$3S + S + S - 3 - 3 - 6 = 58$
$5S - 12 = 58$
$5S = 58 + 12$
$5S = 70$
$S = \frac{70}{5}$
$S = 14$
So, the son's present age is 14 years.
Vanraj's present age is $3S$. Substitute the value of $S$:
Vanraj's present age = $3 \times 14 = 42$ years.
The ratio of present ages of A and B is 7 : 8. After 6 years from now, the ratio of their ages will be 8 : 9. If C's present age is 10 years more than the present age of A, then the present age (in years) of C is:
Three years ago, the ratio of the age of father to that of his son was 8 ∶ 3. After 4 years, their ages will be in the ratio 11 ∶ 5. What is the present age (in years) of the father?
At present, A is younger than B by 8 years. If 4 years ago, their ages were in the ratio 1 ∶ 2, then what is the present age of B (in years)?
Eight years ago, the ratio of ages of A and B was 5 ∶ 4. The ratio of their present ages is 6 ∶ 5. What will be the sum (in years) of the ages of A and B after 7 years from now?
Ratio of the present age of a mother to that of the daughter is 7 ∶ 1. After 5 years the ratio will become 4 ∶ 1. What is the difference (in years) in their present ages?