Arvind buys an item for ₹x. He sells it to Beeru at a loss of 5%. Beeru spends ₹152 on its transportation and sells it to Meenu at a profit of 56%. If Meenu buys it for ₹1,482, then what is the value of x?
840
Arvind's cost = ₹x. He sells to Beeru at 5% loss, so Beeru's purchase price = 0.95x.
Beeru's total cost including transport = 0.95x + 152. He sells to Meenu at 56% profit, so selling price = 1.56 × (0.95x + 152).
Given 1.56 × (0.95x + 152) = 1482
0.95x + 152 = 1482 / 1.56 = 950
0.95x = 950 − 152 = 798
x = 798 / 0.95 = 840.
Hence, the correct answer is 840.
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Important Questions from Profit and Loss
- Veer bought some sharpeners at the rate of ₹180/dozen. He sold them for ₹23 each. His profit percentage is ____ % (rounded off to two decimal places).
- A shopkeeper lists the price of a fan at 60% above its cost price and offers a 15% discount on its list price. If he earns a profit of ₹117, then what is the list price (in ₹) of the fan?
- The marked price of an article is ₹800. It is sold at two successive discounts of 24% and 15%, respectively. Find the selling price of the article.
- A discount of 13% on the marked price of an article is allowed and then the article is sold for ₹348. The marked price of the article is:
- A trader claims to sell grains at a profit of 29%, but also dishonestly uses a weight which is 13% less than what is mentioned on it. Find the total percentage of profit earned by the trader. (Round off the answer to the nearest whole number.)
