This problem involves calculating the final selling price of an article after applying two consecutive percentage discounts to its marked price.
The marked price (MP) is given as ₹800.
There are two successive discounts:
The first discount is 24% of the marked price.
Discount Amount 1 = $24\%$ of ₹800
Discount Amount 1 = $ \frac{24}{100} \times 800 $
Discount Amount 1 = $ 24 \times 8 $
Discount Amount 1 = $ ₹192 $
Price after the first discount = Marked Price - Discount Amount 1
Price after first discount = $ ₹800 - ₹192 $
Price after first discount = $ ₹608 $
The second discount is 15% of the price after the first discount (which is ₹608).
Discount Amount 2 = $15\%$ of ₹608
Discount Amount 2 = $ \frac{15}{100} \times 608 $
Discount Amount 2 = $ 0.15 \times 608 $
Discount Amount 2 = $ ₹91.20 $
The final selling price (SP) is the price after the first discount minus the second discount amount.
Selling Price = Price after first discount - Discount Amount 2
Selling Price = $ ₹608 - ₹91.20 $
Selling Price = $ ₹516.80 $
We can also calculate the selling price directly using the formula:
SP = MP $ \times (1 - \frac{\text{Discount 1}}{100}) \times (1 - \frac{\text{Discount 2}}{100}) $
SP = $ 800 \times (1 - \frac{24}{100}) \times (1 - \frac{15}{100}) $
SP = $ 800 \times (1 - 0.24) \times (1 - 0.15) $
SP = $ 800 \times (0.76) \times (0.85) $
SP = $ 800 \times 0.646 $
SP = $ 516.80 $
Therefore, the selling price of the article after applying the two successive discounts of 24% and 15% is ₹516.80.