Arvind bought an article for ₹x. He sold it to Biru at a loss of 15%. Biru spent ₹122 on its transportation and sold it to Minu at a profit of 50%. If Minu bought it for ₹1968, then what is the value of x?
1400
Arvind sold to Biru at 15% loss, so Biru's cost = 0.85x.
Biru's total cost after ₹122 transport = 0.85x + 122.
Biru sold to Minu at 50% profit, so Minu's cost = 1.5 × (0.85x + 122) = 1968.
Therefore 0.85x + 122 = 1968 ÷ 1.5 = 1312, giving 0.85x = 1190 and x = 1190 ÷ 0.85 = 1400.
Hence, the value of x is ₹1400.
Similar Questions
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Important Questions from Successive Selling
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- A dealer buys two articles X and Y for ₹1,000 each. He marks each of them at the same price. He sells X by giving two successive discounts of 15% and 30% and still earns ₹337 as profit. If he sells Y at a single discount of 49%, then what is the profit percentage on Y?
- Find the single equivalent discount (rounded off to two decimal places) for successive discounts of 18%, 6% and 25%.
A shopkeeper marks the price of three identical articles, first, 60% above the Cost Price; second, 45% above the Cost Price and the third, 40% above the cost price. If he gives discount of 25% on first article, 20% on the second article and 15% on the third one, what is his overall profit percentage?
A dealer bought a six-seater Dining Table after getting successive discounts of 15% and 12%. Thereafter, he spent 10% on transport, etc. and finally sold it for Rs. 24,169.75, thereby earning a profit of 25%. What was the marked price of the Dining Table?
