The problem states that Arun is 25% more efficient than Bobby. This means Arun completes more work in the same amount of time compared to Bobby.
Let's represent Bobby's efficiency (work done per day) as $E_B$. Since Arun is 25% more efficient, Arun's efficiency ($E_A$) can be written as:
$E_A = E_B + 0.25 \times E_B$
$E_A = (1 + 0.25) E_B$
$E_A = 1.25 E_B$
We can express this relationship as a ratio:
$\frac{E_A}{E_B} = 1.25 = \frac{125}{100} = \frac{5}{4}$
This ratio indicates that for every 4 units of work Bobby does, Arun does 5 units.
We know that the time taken to complete a job is inversely proportional to the efficiency or work rate.
Arun alone can complete the job in 15 days. Let the total amount of work be $W$.
Arun's work rate ($R_A$) is:
$R_A = \frac{\text{Total Work}}{\text{Time taken by Arun}} = \frac{W}{15}$ (units of work per day)
Since the ratio of efficiencies is $\frac{E_A}{E_B} = \frac{5}{4}$, the ratio of their work rates is the same: $\frac{R_A}{R_B} = \frac{5}{4}$.
We can find Bobby's work rate ($R_B$) using Arun's rate:
$R_B = \frac{4}{5} \times R_A$
$R_B = \frac{4}{5} \times \frac{W}{15}$
$R_B = \frac{4W}{75}$ (units of work per day)
When Arun and Bobby work together, their work rates add up. The combined work rate ($R_{A+B}$) is:
$R_{A+B} = R_A + R_B$
$R_{A+B} = \frac{W}{15} + \frac{4W}{75}$
To add these fractions, we find a common denominator, which is 75:
$R_{A+B} = \frac{5 \times W}{5 \times 15} + \frac{4W}{75}$
$R_{A+B} = \frac{5W}{75} + \frac{4W}{75}$
$R_{A+B} = \frac{5W + 4W}{75}$
$R_{A+B} = \frac{9W}{75}$
Simplifying the fraction:
$R_{A+B} = \frac{3W}{25}$ (units of work per day)
The time it takes for them to complete the job working together is the total work divided by their combined rate:
Time Together = $\frac{\text{Total Work}}{\text{Combined Work Rate}}$
Time Together = $\frac{W}{R_{A+B}}$
Time Together = $\frac{W}{\frac{3W}{25}}$
To divide by a fraction, we multiply by its reciprocal:
Time Together = $W \times \frac{25}{3W}$
Time Together = $\frac{25}{3}$ days
To express this as a mixed number:
$\frac{25}{3} = 8 \text{ remainder } 1$
So, Time Together = $8\frac{1}{3}$ days.
Therefore, Arun and Bobby working together will take $8\frac{1}{3}$ days to complete the job.
Three pipes A, B and C can fill a tank in $10$, $15$ and $20$ hours respectively. Pipe A was opened at $6$ AM, pipe B at $7$ AM and pipe C at $8$ AM. At what time was the tank completely filled, if pipe C needs a break of $1$ hour after remaining open for $3$ hours?
A tank has four pipes $P_1$, $P_2$, $P_3$ and $P_4$. The tank can be filled in $15$ minutes by pipes $P_1$, $P_2$, $P_3$ together. It can be filled in $20$ minutes by pipes $P_2$, $P_3$, $P_4$ together and it can be filled by pipes $P_1$, $P_4$ together in $30$ minutes. If all the pipes are opened together, then in how much time will the tank be filled?
$5$ men and $4$ women can earn ₹ $20000$ in $8$ days. $10$ men and $7$ women can earn ₹ $23,750$ in $5$ days. In how many days will $5$ men and $6$ women earn ₹ $12,000$?