Arjun travelled from place A to place B by car at a speed of 48 km/hr and returned back to place A at a speed of 60 km/hr. He then again went to place B at a speed of 72 km/hr. Find the average speed of the car for the whole journey (rounded off to two decimal places).
58.38 km/hr
Let the distance AB = 720 km (LCM of 48, 60 and 72). Total distance = 3 × 720 = 2160 km.
Total time = \(\frac{720}{48} + \frac{720}{60} + \frac{720}{72}\) = 15 + 12 + 10 = 37 hours.
Average speed = \(\frac{2160}{37}\) = 58.378… ≈ 58.38 km/hr.
Hence, the answer is 58.38 km/hr.
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