An object is placed of 20 cm in front of a concave mirror and its image is formed at a distance of 60 cm on the same side as the object. The magnification produced by the mirror will be:
- 3
The correct answer is option 4 I.e. -3.
Object distance, u=−20 cmu = -20 \, ext{cm} (negative, since it's in front of the mirror)
Image distance, v=−60 cmv = -60 \, ext{cm} (negative, since the image is also on the same side — real image)
Magnification (M) is given by:M = v / u = − 60 / −20 = -3
The magnitude 3 means the image is three times larger than the object.
The negative sign indicates that the image is real and inverted.
So, the magnification produced by the mirror is –3.
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