An iron nail dipped in copper sulphate solution turns brown. This is due to which one of the following types of reactions?
Displacement reaction
When an iron nail is dipped in a copper sulphate solution, a chemical reaction occurs. You observe that the iron nail gets a brown coating, and the blue colour of the copper sulphate solution fades and turns greenish.
This change happens because iron is more reactive than copper. According to the reactivity series of metals, a more reactive metal can displace a less reactive metal from its salt solution.
The reaction that takes place is between iron (Fe) metal and copper sulphate (CuSO\(_4\)) solution. The balanced chemical equation for this reaction is:
\(\text{Fe(s)} + \text{CuSO}_4\text{(aq)} \rightarrow \text{FeSO}_4\text{(aq)} + \text{Cu(s)}\)
In this reaction:
A displacement reaction is a chemical reaction in which a more reactive element displaces a less reactive element from its compound. In this case, iron (Fe) is more reactive than copper (Cu), so iron displaces copper from the copper sulphate (CuSO\(_4\)) solution.
The brown coating on the iron nail is the displaced copper metal. The change in the colour of the solution from blue (copper sulphate) to green (iron sulphate) further confirms the reaction.
Therefore, based on the definition and the observed changes, the reaction between iron and copper sulphate is a displacement reaction.
| Reaction Type | Description | Example |
|---|---|---|
| Displacement | A more reactive element replaces a less reactive one from its compound. | \( \text{Fe} + \text{CuSO}_4 \rightarrow \text{FeSO}_4 + \text{Cu} \) |
| Addition | Two or more substances combine to form a single substance. | \( \text{C}_2\text{H}_4 + \text{H}_2 \rightarrow \text{C}_2\text{H}_6 \) |
| Decomposition | A single compound breaks down into two or more simpler substances. | \( \text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2 \) |
| Component | Initial State | Final State |
|---|---|---|
| Iron Nail (Fe) | Shiny grey solid | Coated with brown solid (Cu) |
| Copper Sulphate Solution (CuSO\(_4\)) | Blue solution | Green solution (FeSO\(_4\)) |
The reactivity series of metals lists metals in order of their decreasing reactivity. A metal higher up in the series can displace a metal lower down from its salt solution or oxide.
Common Reactivity Series (excerpt):
K > Na > Ca > Mg > Al > Zn > Fe > Pb > Cu > Ag > Au
Since iron (Fe) is placed above copper (Cu) in the reactivity series, iron is more reactive than copper. This higher reactivity allows iron to displace copper ions (Cu\(^{2+}\)) from the copper sulphate solution, forming iron(II) sulphate and solid copper metal.
This type of reaction is a classic example used to illustrate the concept of single displacement reactions, where one element displaces another from a compound.
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Consider the following reaction:
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Match List I with List II and select the correct answer using the code given below the Lists:
LIST I (Chemical process) | LIST II (Reaction) | ||
A. | Electrolysis of water | 1. | Double displacement |
B. | Burning of coal | 2. | Combination reaction |
C. | Iron nail immersed in copper sulphate solution | 3. | Decomposition reaction |
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