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Question

An electron and a proton starting from rest get accelerated through potential difference of 100 kV. The final speeds of the electron and the proton are V e and V p respectively. Which one of the following relations is correct?

This question was previously asked in
CDS I 2019 Elementary Mathematics Previous Year Paper (03-Feb-2019)
The correct answer is

V e> V p

Understanding Charged Particle Acceleration

When a charged particle is accelerated by a potential difference, the work done by the electric field on the particle is converted into kinetic energy. This principle helps us determine the final speed of the particle.

Let's consider a charged particle with charge magnitude \(|q|\) and mass \(m\). When it is accelerated through a potential difference \(V\), the work done (\(W\)) on the particle is given by:

\[W = |q|V\]

If the particle starts from rest, its initial kinetic energy is zero. The final kinetic energy (\(KE_f\)) after being accelerated through the potential difference is equal to the work done:

\[KE_f = W\]

The kinetic energy of a particle with speed \(v\) is given by:

\[KE = \frac{1}{2}mv^2\]

So, equating the work done and the final kinetic energy:

\[|q|V = \frac{1}{2}mv^2\]

We can rearrange this equation to find the final speed \(v\):

\[v^2 = \frac{2|q|V}{m}\]

\[v = \sqrt{\frac{2|q|V}{m}}\]

Comparing Speeds of Electron and Proton

We are given that an electron and a proton are accelerated through the same potential difference, \(V = 100 \text{ kV}\). Both particles start from rest.

Let's consider the electron:

  • Charge magnitude, \(|q_e| = e\) (where \(e\) is the elementary charge)
  • Mass, \(m_e\)
  • Potential difference, \(V\)
  • Final speed, \(v_e\)

The speed of the electron will be:

\[v_e = \sqrt{\frac{2e V}{m_e}}\]

Now let's consider the proton:

  • Charge magnitude, \(|q_p| = e\) (the charge of a proton is \(+e\), so the magnitude is \(e\))
  • Mass, \(m_p\)
  • Potential difference, \(V\)
  • Final speed, \(v_p\)

The speed of the proton will be:

\[v_p = \sqrt{\frac{2e V}{m_p}}\]

Analyzing the Speed Relation

We have the expressions for \(v_e\) and \(v_p\):

\[v_e = \sqrt{\frac{2e V}{m_e}} \quad \text{and} \quad v_p = \sqrt{\frac{2e V}{m_p}}\]

Notice that the term \(2eV\) is the same for both the electron and the proton, as they have the same magnitude of charge (\(e\)) and are accelerated through the same potential difference (\(V\)).

The speed is inversely proportional to the square root of the mass:

\[v \propto \frac{1}{\sqrt{m}}\]

This means that if the mass is smaller, the speed will be larger, assuming all other factors are constant.

We know that the mass of an electron (\(m_e\)) is significantly smaller than the mass of a proton (\(m_p\)). Approximately, \(m_p \approx 1836 \times m_e\).

Since \(m_e < m_p\), the denominator in the expression for \(v_e\) is smaller than the denominator in the expression for \(v_p\). Therefore, the value under the square root is larger for the electron.

\[\frac{1}{m_e} > \frac{1}{m_p}\]

\[\frac{2eV}{m_e} > \frac{2eV}{m_p}\]

\[\sqrt{\frac{2eV}{m_e}} > \sqrt{\frac{2eV}{m_p}}\]

Thus, the speed of the electron is greater than the speed of the proton:

\[v_e > v_p\]

This relation matches one of the given options.

Summary of Electron and Proton Speeds

Particle Charge Magnitude Mass Potential Difference Speed Formula
Electron \(e\) \(m_e\) \(V\) \(v_e = \sqrt{\frac{2eV}{m_e}}\)
Proton \(e\) \(m_p\) \(V\) \(v_p = \sqrt{\frac{2eV}{m_p}}\)

Comparing \(v_e\) and \(v_p\), we see that since \(m_e < m_p\), it follows that \(v_e > v_p\).

Revision Table: Key Concepts

Concept Formula / Principle Application Here
Work done by Electric Field \(W = qV\) (for magnitude) Energy gained by particle
Kinetic Energy \(KE = \frac{1}{2}mv^2\) Energy of motion
Energy Conservation \(|q|V = \frac{1}{2}mv^2\) Potential energy converted to kinetic energy
Speed relation to mass \(v \propto \frac{1}{\sqrt{m}}\) (for fixed energy) Lighter particles are faster for same energy
Electron vs Proton Mass \(m_e < m_p\) Electron is much lighter than proton

Additional Information: Electron and Proton Properties

Electrons and protons are fundamental particles with distinct properties that are important in physics:

  • Charge: The electron has a negative charge (\( -e \)), and the proton has a positive charge (\( +e \)). The magnitude of their charge is the same, \(e \approx 1.602 \times 10^{-19} \text{ C}\).
  • Mass: The rest mass of an electron is \(m_e \approx 9.109 \times 10^{-31} \text{ kg}\). The rest mass of a proton is \(m_p \approx 1.672 \times 10^{-27} \text{ kg}\). The proton is about 1836 times more massive than the electron.
  • Acceleration: When accelerated by the same potential difference, they gain the same amount of kinetic energy (since the work done \(W = |q|V\) is the same, and energy is conserved).
  • Speed: Because they gain the same kinetic energy but have different masses, their final speeds will be different. The lighter particle (electron) will have a higher speed.

This problem highlights the inverse relationship between the speed and mass of particles that have gained the same amount of kinetic energy.

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