Speed of Sound Calculation via Echo
An echo occurs when sound waves reflect off a surface. The sound travels from the source (cracker) to the reflecting surface (building) and then back to the observer.
Given:
- Distance to the building, \(d = 99 \text{ m}\)
- Time taken for the echo to be heard, \(t = 0.6 \text{ s}\)
The total distance traveled by the sound wave is twice the distance to the building, as it travels there and back.
Total distance, \(d_{total} = 2 \times d\)
\(d_{total} = 2 \times 99 \text{ m} = 198 \text{ m}\)
The speed of sound (\(v\)) is calculated using the formula:
\(v = \frac{\text{Total Distance}}{\text{Time taken}} = \frac{d_{total}}{t}\)
Substituting the values:
\(v = \frac{198 \text{ m}}{0.6 \text{ s}}\)
\(v = \frac{1980}{6} \text{ m/s}\)
\(v = 330 \text{ m/s}\)
Therefore, the speed of sound is 330 m/s.
Similar Questions
- Sound travels fastest in the medium
Important Questions from The Speed of Sound
An object is 10.64 km below the sea level. A research team sends down a sonar signal to confirm this depth. After how long can it expect to get the echo? Take speed of sound in sea water = 1520 m/s.
A boy stands 83 m in front of a high wall and then blows a whistle, calculate the time interval when he hears an echo. Speed of sound is 332 m/s.
A man claps his hands in front of a wall and he hears an echo after 1.6s. He walks. 33m towards wall and hears the echo 1.4 s after clapping. Then velocity of sound in air is:
For hearing a distinct sound, the time interval between the original sound and the reflected one must be atleast ______ seconds.
Please select the correct option for the assertion-reason statement.
Assertion: The ceiling conference halls are made curved.
Reason: Curved ceilings help the sound to spread evenly in the hall.
